Explain each step, excluding those that are labeled as “no justification needed.” For each step, identify the property of the real numbers being used and explain how that property is being applied. 16(2 + x) 15x - 12 (no justification needed)= (32 + 16x) - 15x-12= (32 + 16x) + (−15x) − 12 (no justification needed)= 32 + (16x + (−15x)) — 12= 32 + (16 + (−15))x - 12= 32 + 1x − 12 (no justification needed)= 1x + 32-12= x + 32-12= x + 20 (no justification needed)

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Explain each step, excluding those that are labeled as “no justification needed.” For each step, identify the property of the real numbers being used and explain how that property is being applied.

Explain each step, excluding those that are labeled as “no justification needed.” For each step, identify the property of the real numbers being used and explain how that property is being applied.

Algebra for College Students

10th Edition

ISBN:9781285195780

Author:Jerome E. Kaufmann, Karen L. Schwitters

Publisher:Jerome E. Kaufmann, Karen L. Schwitters

Chapter9: Polynomial And Rational Functions

Section9.4: Graphing Polynomial Functions

Problem 45PS

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Question

Explain each step, excluding those that are labeled as “no justification needed.” For each step, identify the property of the real numbers being used and explain how that property is being applied.

16(2 + x) 15x - 12 (no justification needed)
= (32 + 16x) - 15x-12
= (32 + 16x) + (−15x) − 12 (no justification needed)
= 32 + (16x + (−15x)) — 12
= 32 + (16 + (−15))x - 12
= 32 + 1x − 12 (no justification needed)
= 1x + 32-12
= x + 32-12
= x + 20 (no justification needed)

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