فأوجد المقدار ، ^5 5 = theta و F2 = 150Ib إذا كان%3DX والاتجاه المقاس في اتجاه عقارب الساعة من المحورالموجب ل لقوة المحصلة ل لقوى الثلاث المؤثرة على* .القوسyF = 52 lb13/ 12F = 80 lb25°ه هانه

Answered: Image /qna-images/answer/c11ad854-c57a-4d39-a835-2b316be0d3e3.jpg

Answered: F = 52 lb 13/ 12 F = 80 lb 25°

Engineering

Mechanical Engineering

F = 52 lb 13/ 12 F = 80 lb 25°

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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