Question
Asked Dec 18, 2019
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A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure below.

 

(d) If the object has a speed of 0.450 m/s at x = 0, find its speed at x = 6.00 m and its speed at x = 16.0 m.

speed at x = 6.00 m =  ?

speed at x = 16.0 m = ?

F, (N)
4
3
2
x (m)
2 4
6.
8
10 12 14 16 18 20
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F, (N) 4 3 2 x (m) 2 4 6. 8 10 12 14 16 18 20

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Expert Answer

Step 1

Given,

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Mass of object,m =3 Kg At x = 0,v, = 0.450 m/s

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Step 2

Area of graph F-x will is equal to work done. 

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F, (N) 1 x (m) B 8 1D12 14 1Ệ 18 20 2 4 3. 2.

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Step 3

Work done between x= 0 to x= 6 m is equal to change in kinetic ...

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Vons =(0B)(4B) 0-6 (6)(4) =12 J 0-6 Wons =m(v; -v}) 12=0[ri-(043"] v -(0.45) - 0-6 2 v -(0.45)* 24 3 v = (0.45)° +8 v = 8.2025 V = 2.86 m/s

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