Question
Asked Dec 12, 2019
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The force acting on a particle varies as in the figure below. (The x axis is marked in increments of 1.50 m.)

Find the work done by the force as the particle moves across the following distances.

(a) from 
x = 0 m to x = 12.0 m

 

(b) from 
x = 12.0 m to x=18.0m 



(c) from 
x = 0 m to x=18.0m

 
F, (N)
B.
G E,
x (m)
-2
D
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F, (N) B. G E, x (m) -2 D

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Expert Answer

Step 1

(a)

 

The work done by the force as the particles moves from x=0 to x=12.0 m, that equals the area under graph, can be calculated as,

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W, =R)(4 =(6 N)(12-0) m) (F)(d.) = 36 N · m = 36 J

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Step 2

(b)

 

The work done by the force as the particles moves from x=12.0 m to x=18.0 m, tha...

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W; = -(F,)(d,) –3 N)((18–12) m) = -9 N m = -9 J

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Tagged in

Science

Physics

Kinematics