f '(x) = 6x 6.r %3D Part 2 of 8 f(xn) We know that Xn + 1 Xn¯ F '(xn) Therefore, %3D - 6. Xn -48 48 Xn + 1 = Xp- 6 Xn

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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BEMAN..
f "(x) = 6x°
6r
Part 2 of 8
f(xn)
f '(xn)
We know that Xn + 1 = Xn
Therefore,
Xn
48
48
Xn + 1= Xn
5.
6 Xn
Part 3 of 8
6.
Since V64 = 2, and 64 is reasonably close to 48, we'll use x1 = 2. This gives us
f(2)
f '(2)
X2 = 2
|
%3|
2-
64 X
16
192
1.91666667
1.91666667 (rounded to eight decimal places)
Part 4 of 8
Now we can find x3.
1.916666676
X3 = 1,91666667
))
%3D
x (rounded to eight decimal places)
Enter a numnber.
Transcribed Image Text:E Apps New folder SharePoint Resources BEMAN.. f "(x) = 6x° 6r Part 2 of 8 f(xn) f '(xn) We know that Xn + 1 = Xn Therefore, Xn 48 48 Xn + 1= Xn 5. 6 Xn Part 3 of 8 6. Since V64 = 2, and 64 is reasonably close to 48, we'll use x1 = 2. This gives us f(2) f '(2) X2 = 2 | %3| 2- 64 X 16 192 1.91666667 1.91666667 (rounded to eight decimal places) Part 4 of 8 Now we can find x3. 1.916666676 X3 = 1,91666667 )) %3D x (rounded to eight decimal places) Enter a numnber.
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