f (x) = - x² - 2 as x → -0 f (x) – as x → -o f(x) →-∞ as x → +∞ f (x) → +∞ as x → +o0 ƒ (x) as x - -0 f (x) as x → -00 f (x) as X- +oo f(x) as x → +0 f(x)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 64E
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Using the following polynomial to describe the end behavior
f (x) = - x² – 2
%3D
as x -of (x) → -∞
as x -∞ f(x) → -∞
as x +oof (x)
as x → +00 S) → +oo
as x
+oo
as x -00 f(x) → +00
as X
+oo/(x)
as x-+00f(x) → +00
Transcribed Image Text:f (x) = - x² – 2 %3D as x -of (x) → -∞ as x -∞ f(x) → -∞ as x +oof (x) as x → +00 S) → +oo as x +oo as x -00 f(x) → +00 as X +oo/(x) as x-+00f(x) → +00
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