Please answer asap thanks F1 lbF2 Ib/ftF3 lb/ftA,FB.D E1 3 ft 6 ft9 ft| 3 ft9 ftF1= 12, F2 = 15, F3 = 21erive the shear equation of segment AB.Your answerDerive the moment equation of segmentABIJ/ Derive the shear equation of segment BC. *Your answerDerive the moment equation of segment BC.Your answerDerive the shear equation of segment CD.*Your answerDerivethe momentequationof sD."egment CD.YouranswerDerivethe sneareouationof segment DE

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Answered: F1 lb F2 Ib/ft F3 Ib/ft A B| D E 3 ft 6…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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W=1317 kN/mUsing Three Moment Equation, determine all reactions at supports also, determine shear andbending moments with complete labels. Use 1= 1/12 bh^3 and E = 2.15x10^7 KPa
Q9c. For the beam below, the point loads and distances are as follows: F1 = 11. 25 kN, F2 = 11.25 kN and F3 = 4.50 kN L1 = 2.25 m, L2 = 4.50 m, L3 = 4.50 m and L4 = 2.25 m Determine the bending moment at D. Give your answer in kilonewton metres (kNm) to two decimal places.
Five forces are applied to the beam trolley as shown. Determine the y-coordinate of the point on the y-axis through which the stand-alone resultant R must pass if F = 6.0 kN and θ = 40°. Point O is at the center of the I-beam.
A rigid beam with negligible mass is pinned at one end and supported by two rods. The beam was initially horizontal before the load P was applied. 1. Compute the elongation of steel if P=120kN 2. Compute the elongation of steel if P=120kN 3. Find the vertical movement of P if P=120kN
Given P1=00K P2=19K UNKNOWN: 1. FORCE IN MEMBER GF 2. FORCE IN MEMBER FC 3. FORCE IN MEMBER CD
Dead Load= 20 kN/mLive Load= 30 kN/mUnit weight of concrete= 23.56 kN/cu.mf'c= 27.6 MPafy= 414 MPaCompute the shear and moment diagram.
5. What is the approximate moment at support a? In kN.m A. -79.86 B. -27.95 C. -73.28 D. 0 E. -10.98 F. 73.28 G. 79.86 H. 10.98 I. 27.95
The 600mm diameter steel shaft is subjected to the torques shown. Determine torsion at each section. Assume G = 75 GPa. P=74 1.5P= 1.5(74) = 111 kNm 3P= 3(74)= 222kNm
BP4: A cantilevered beam (cantilevered at its left end) of length L is loaded with a uniformly distributed load of w over its length and two concentrated loads F1 at L/3 from left and F2 at 2L/3 from left. Determine the reactions if F1=2F2=wL. I solved this problem: I got R1=5/2 wL and MR1=7/6wL^2 for cantilever moment going counterclockwise. >>>MY QUESTION:Solve shear and bending moment diagram using GRAPHICAL METHOD. Thanks!<<
Use Area-Moment Method in solving the problem. Consider 150 mm x 150 mm section and E = 80 GPa. A=2.8 B=24.0 C=28 Determine: Vertical Reaction at B in kN. Moment Reaction at A in kN-m.
M1 at point B is 10 kips-ft, P1=12 kips is 9 ft from point A; and w1 = 1.5kips/ft is distributed along the length of the beam which is 22 ft. If the1.5kips/ft uniformly distributed load will be transformed into a singularconcentrated load, what will be the magnitude of Moment taken at pointA? What is the equivalent singular Resultant force of the loads shown?Determine the location of the resultant R from point A.
Properties: • b1 = 300 mm • b2 = 180 mm • d1 = 250 mm • d2 = 350 mm • f'c = 28 MPa • fy = 414 MPa • eccentricity = 200 mm Determine the following: 1. Location of the plastic centroid measured from the y-axis in mm 2. Depth of the compression block in mm 3. Nominal Axial in kN 4. Moment Capacity in kN-m

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F1 lb F2 Ib/ft F3 Ib/ft A B| D E 3 ft 6 ft 9 ft 3 ft 9 ft F1= 12, F2 = 15, F3 = 21 Derive the shear equation of segment AB." Your answer 9, 3. C. 6.