Answered: Figure < 1 of 1 3.00 μF 5.00 μF be 6.00…

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Electrical Engineering

Figure < 1 of 1 3.00 μF 5.00 μF be 6.00 μF

EBK ELECTRICAL WIRING RESIDENTIAL

19th Edition

ISBN:9781337516549

Author:Simmons

Publisher:Simmons

Chapter1: General Information For Electrical Installations

Section: Chapter Questions

Problem 14R

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Question

In the circuit shown in (Figure 1), the potential difference across abab is 23.5 V. Calculate the charge on the 3.00 μF capacitor, the charge on the 5.00 μF capacitor, the charge on the 6.00 μF capacitor, and the potential difference across the 3.00 μF capacitor

Expert Solution

Step 1

Given

Voltage across ab terminal V_ab = 23.5 V

In capacitor charge Q =CV

Voltage across 3 μF capacitor $\begin{array}{rcl} V_{c_{1}} & = & \frac{3}{8} * 23.5 \\ V_{c_{1}} & = & 8.8125 V \end{array}$

Charge across 3 μF capacitor $Q_{c_{1}} = 3 * 10^{6} * 8.8125 Q_{c_{1}} = 26.437 μC$

Voltage across 5 μF capacitor $V_{c_{2}} = \frac{5}{8} * 23.5 V_{c_{2}} = 14.68 V$

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