Fill in the blank so that a program is constructed where the user enters a sentence, and it finds out the number of digits and letters within the sentence.
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C
Fill in the blank so that a program is constructed where the user enters a sentence, and it finds out the number of digits and letters within the sentence.
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- using this c++ code add these improvements -want to ignore whitespace -allow number #include <stdio.h> #include <ctype.h> #include <stdlib.h> int lookahead; void expr(void); void rest(void); void term(void); void match(int); void error(void); int main(void) { lookahead = getchar(); expr(); putchar('\n'); /* adds trailing newline character */ } void term(void) { if (isdigit(lookahead)) { putchar(lookahead); match(lookahead); } else error(); } void match(int t) { if (lookahead == t) lookahead = getchar(); else error(); } void error(void) { printf("syntax error\n"); /* print error message */ exit(1); /* then halt */ } void expr(void) { term(); while ( 1) { if (lookahead == '+') { match('+'); term(); putchar('+'); } else if (lookahead == ' - ') { match(' - '); term(); putchar(' - '); } else break; } }This is the code so far #include <iostream> // for cin and cout#include <iomanip> // for setw() and setfill()using namespace std; // so that we don't need to preface every cin and cout with std:: void printSpaces(int n, int end){for (int j = n; j > end; j--){cout << " ";}}void printFirstTwoBuildingSection(int n, int startSpacing){int start = 2 * ((n / 2) - 1), end = 0;for (int i = 0; i < n; i++){printSpaces(startSpacing, 0);cout << "|";if (i < (n / 2)){printSpaces(i, 0);cout << "\\";printSpaces(start, 0);cout << "/";start -= (2);printSpaces(i, 0);cout << "|" << endl;}else{printSpaces(n - i - 1, 0);cout << "/";printSpaces(end, 0);cout << "\\";end += (2);printSpaces(n - i - 1, 0);cout << "|" << endl;}}printSpaces(startSpacing, 0);cout << "/";for (int i = 0; i < n; i++){cout << "-";}cout << "\\" << endl;}int main(){int menuOption = 0; cout << "Choose from among the following…#include <stdio.h> struct Single { int num; }; void printSingle(int f) { int binaryNum[33]; int i = 0; while(f>0) { binaryNum[i] = f % 2; f = f/2; i++; } for (int j=i-1; j>= 0; j--) { printf("%d",binaryNum[j]); } } int main() { struct Single single; single.num = 33; printf("Number: %d\n",single.num); printSingle(single.num); return 0; }
- #include <stdio.h>#include <string.h> struct user { char user_name[10]; char bank_name[10]; int account_num[4]; int card_number[14]; int pass[4]; int balance; int wallet_num[11];}; int num_acc;int withdrawal;int deposition;char transaction;int k;int number_of_papers;int choice4; void print_array(int arr[], int size){ for (int i = 0; i < size; i++) { printf("%d", arr[i]); } printf("\n");} void print_struct(char username[], char bankname[], int accountnum[], int size3, int cardnum[], int size4, int balance){ printf("Username is %s", username); printf("\nBankname is %s\n", bankname); printf("Account number is "); print_array(accountnum, size3); printf("Cardnumber is "); print_array(cardnum, size4); printf("Balance is %d\n", balance);} void scan_array(int arr[], int size){ for (int i = 0; i < size; i++) { scanf_s("%d", &arr[i]); } } int search_name_in_array(struct user user[], int size1, char…#ifndef lab5ExF_h #define lab5ExF_h typedef struct point { char label[10]; double x ; // x coordinate for point in a Cartesian coordinate system double y; // y coordinate for point in a Cartesian coordinate system double z; // z coordinate for point in a Cartesian coordinate system }Point; void reverse (Point *a, int n); /* REQUIRES: Elements a[0] ... a[n-2], a[n-1] exists. * PROMISES: places the existing Point objects in array a, in reverse order. * The new a[0] value is the old a[n-1] value, the new a[1] is the * old a[n-2], etc. */ int search(const Point* struct_array, const char* target, int n); /* REQUIRES: Elements struct-array[0] ... struct_array[n-2], struct_array[n-1] * exists. target points to string to be searched for. * PROMISES: returns the index of the element in the array that contains an * instance of point with a matching label. Otherwise, if there is * no point in the array that its label matches the target-label, * it should return -1. * If there are more than…Following code is for 4×4 tic toc toe game covert this code in to 3×3 players. Code #include <iostream> using namespace std; class Board { char board[4][4]; public: Board() { for(int i=0;i<4;i++) { for(int j=0;j<4;j++) { board[i][j]='_'; } } } void printBoard() { for(int i=0;i<4;i++) { for(int j=0;j<4;j++) { cout<<board[i][j]<<'|'; } cout<<endl; } cout<<endl; } int setPosition(char choice) { while(1) { int row,column; cout<<"Please enter the row and column"<<endl; cin>>row>>column; if(board[row][column]=='_') { board[row][column]=choice; break; } else { cout<<"Position is taken"<<endl; } } } char getPosition() { for(int i=0;i<4;i++) { for(int j=0;j<4;j++) { return board[i][j]; } } } int checkHorizontal(char choice) { int count; for(int i=0;i<4;i++) {…
- #include<stdio.h> #include<stdarg.h> void fun1(int num, ...); void fun2(int num, ...); int main() { fun1(1, "Apple", "Boys", "Cats", "Dogs"); fun2(2, 12, 13, 14); return 0; } void fun1(int num, ...) { char *str; va_list ptr; va_start(ptr, num); str = va_arg(ptr, char *); printf("%s ", str); } void fun2(int num, ...) { va_list ptr; va_start(ptr, num); num = va_arg(ptr, int); printf("%d", num); }.Please Help In JAVA Here is the skeleton of a code for insertion sorting in an imperative language. You have to add right lines of codes for the language you choose (C, C++, C#, JAVA etc,). The following sample is for C++. #include <iostream>#include <array>#include <stdio.h>#include <stdlib.h>#include <ctime>using namespace std; void insertionSort(int A[], int n){for (int i = n-2; i >= 0; i--){ int j; int v = A[i]; for (j = i + 1; j <= n-1; j++) { if (A[j] > v) break; else A[j-1] = A[j]; } A[j-1] = v;}} int *randomArray(int n){srand((unsigned) time(0));int * A = new int [n];for (int i = 0; i < n; i++){ A[i] = rand();}return A;} Sample function calls (call these functions in main driver function):int n = 100000;int * A = randomArray(n);insertionSort(A, n);delete [] A; Note: delete memory of first array before sorting second array. After you modify the code: (1) Generate 100, 000 random numbers and sort them (2) Generate 300000…c++ Modify the following so that it uses smart pointers instead of raw pointers. // This program illustrates the use of constructors// and destructors in the allocation and deallocation of memory.#include <iostream>#include <string>using namespace std; class Squares{private:int length; // How long is the sequenceint *sq; // Dynamically allocated arraypublic:// Constructor allocates storage for sequence// of squares and creates the sequenceSquares(int len){length = len;sq = new int[length];for (int k = 0; k < length; k++){sq[k] = (k+1)*(k+1);}// Tracecout << "Construct an object of size " << length << endl;}// Print the sequencevoid print(){for (int k = 0; k < length; k++)cout << sq[k] << " ";cout << endl;}// Destructor deallocates storage~Squares(){delete [ ] sq;// Tracecout << "Destroy object of size " << length << endl;}}; //***********************************************// Outputs the sequence of squares in a…
- #include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…#include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…