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Find a possible formula for the graph. -8 -7 -6 -5 4 -3-2-1 5678 O g(x) = kx(x + 1)(x– 2) for any positive k. O g(x) = – kx(x + 1)(x – 2) for any positive k. O g(x) = kx(x – 1)(x+ 2) for any positive k. g(x) = k(x + 1)(x+ 2) for any positive k. – kx(x – 1)(x+ 2) for any positive k. %3D %3D

Find a possible formula for the graph. -8 -7 -6 -5 4 -3-2-1 5678 O g(x) = kx(x + 1)(x– 2) for any positive k. O g(x) = – kx(x + 1)(x – 2) for any positive k. O g(x) = kx(x – 1)(x+ 2) for any positive k. g(x) = k(x + 1)(x+ 2) for any positive k. – kx(x – 1)(x+ 2) for any positive k. %3D %3D

College Algebra
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter3: Polynomial And Rational Functions
Section: Chapter Questions
Problem 5CC
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Find a possible formula for the graph. y -8 -7 -6 -5 4 -3-2-1 45678 O g(x) = kx(x + 1)(x– 2) for any positive k. O g(x) = – kx(x + 1)(x – 2) for any positive k. O g(x) = kx(x – 1)(x+ 2) for any positive k. O g(x) = k(x + 1)(x + 2) for any positive k. – kx(x-1)(x+ 2) for any positive k. %3D
Transcribed Image Text:Find a possible formula for the graph. y -8 -7 -6 -5 4 -3-2-1 45678 O g(x) = kx(x + 1)(x– 2) for any positive k. O g(x) = – kx(x + 1)(x – 2) for any positive k. O g(x) = kx(x – 1)(x+ 2) for any positive k. O g(x) = k(x + 1)(x + 2) for any positive k. – kx(x-1)(x+ 2) for any positive k. %3D
The graph in the figure is of a polynomial. The window is large enough to show end behavior. (a) What is the minimum possible degree of the polynomial? (b) Is the leading coefficierwof the polynomial positive or negative?
Transcribed Image Text:The graph in the figure is of a polynomial. The window is large enough to show end behavior. (a) What is the minimum possible degree of the polynomial? (b) Is the leading coefficierwof the polynomial positive or negative?
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