Find all absolute and relative extreme values of the function f (x) = x° – 3x² + 6, on the interval [-1, 1].O The absolute maximum is f(1) = 4 and the absolute minimum is f(-2) = -14.O The absolute maximum is f(0) = 6 and the absolute minimum is f(-1) = 2.O The absolute maximum is f(1) = 4 and the absolute minimum is f(-1) = 0.O The absolute maximum is f(0) = 6 and the absolute minimum is f(-1) = -14. Find all absolute and relative extreme values of the function f (x) =2x2 + 5x – 1, on the interval [-4, 0].O The absolute maximum is f(-1.25) = -4 and the absolute minimum is f(-4) = 11.%3DO The absolute maximum is f(-4) = 11 and the absolute minimum is f(-1.25) = -4.O The absolute maximum is f(-2) = -3 and the absolute minimum is f(-1.25) = -4.O The absolute maximum is f(-4) = 11 and the absolute minimum is f(-1) = 0.

here we need to find the absolute maximum and absolute minimum values. the solution is following.

Find all absolute and relative extreme values of the function f(x) = x – 3x² + 6, on the interval [-1, 1]. O The absolute maximum is f(1) = 4 and the absolute minimum is f(-2) = -14. O The absolute maximum is f(0) = 6 and the absolute minimum is f(-1) = 2. %3D O The absolute maximum is f(1) = 4 and the absolute minimum is f(-1) = 0. O The absolute maximum is f(0) = 6 and the absolute minimum is f(-1) = -14. %3D

Find all absolute and relative extreme values of the function f(x) = x – 3x² + 6, on the interval [-1, 1]. O The absolute maximum is f(1) = 4 and the absolute minimum is f(-2) = -14. O The absolute maximum is f(0) = 6 and the absolute minimum is f(-1) = 2. %3D O The absolute maximum is f(1) = 4 and the absolute minimum is f(-1) = 0. O The absolute maximum is f(0) = 6 and the absolute minimum is f(-1) = -14. %3D

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter4: Polynomial And Rational Functions

Section4.5: Rational Functions

Problem 51E

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