Find all the x-values at which the critical points occur of the function f(x)-5x319x+ 10x on the interval [0, 4](Give your answer in the form of a comma-separated list. Express numbers in exact form. Use symbolic notation and fractionswhere needed. Enter DNE if there are no critical points.)x-values at which the critical points occur:Find the extreme values of the function /on the interval [0, 4].(Use decimal notation. Give your answers to three decimal places.)fminmaxQuestion Source: Rogawski 4e Calculhelpprivacy policyterms of useabout useontact uscareers

Question
Asked Oct 25, 2019
Find all the x-values at which the critical points occur of the function f(x)-
5x3
19x
+ 10x on the interval [0, 4]
(Give your answer in the form of a comma-separated list. Express numbers in exact form. Use symbolic notation and fractions
where needed. Enter DNE if there are no critical points.)
x-values at which the critical points occur:
Find the extreme values of the function /on the interval [0, 4].
(Use decimal notation. Give your answers to three decimal places.)
fmin
max
Question Source: Rogawski 4e Calcul
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Find all the x-values at which the critical points occur of the function f(x)- 5x3 19x + 10x on the interval [0, 4] (Give your answer in the form of a comma-separated list. Express numbers in exact form. Use symbolic notation and fractions where needed. Enter DNE if there are no critical points.) x-values at which the critical points occur: Find the extreme values of the function /on the interval [0, 4]. (Use decimal notation. Give your answers to three decimal places.) fmin max Question Source: Rogawski 4e Calcul help privacy policy terms of use about us eontact us careers

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check_circleExpert Solution
Step 1

Consider the given function.

f(x)=5x-19x210x
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f(x)=5x-19x210x

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Step 2

Now, to finding the critical points of the given function.

On differentiating with respect to x, we get

f'(x) 15x-38x + 10
Put fx)0
15x-38.x10 = 0
By using Dharacharya rule:
(-38)t{(-38) -4x15x 10
2x15
38t1444-600
30
38t 844
30
38 2/211
30
19t211
15
19 211
19 211
or x=
15
15
x = 2.235
or x 0.298
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f'(x) 15x-38x + 10 Put fx)0 15x-38.x10 = 0 By using Dharacharya rule: (-38)t{(-38) -4x15x 10 2x15 38t1444-600 30 38t 844 30 38 2/211 30 19t211 15 19 211 19 211 or x= 15 15 x = 2.235 or x 0.298

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Step 3

x-values at which the crit...

19+211 19-211
15
15
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19+211 19-211 15 15

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