Find an equation of the tangent line to the curve at the given point. Illustrate by graphing the curve and the tangent line on the same screen. y = 6x - 5Vx, (1, 1)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 91E
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Find an equation of the tangent line to the curve at the given point. Illustrate by graphing the curve and the
tangent line on the same screen.
y = 6x - 5/x, (1, 1)
Step 1
We can find the equation of a line by using the Point-Slope formula y - Yo = m(x - x). This means that we
need to find the slope m of the line and a point (x Yn) on the line.
We begin by finding the slope. The line tangent to y at (x, Yo) will have the slope m = f'(x,). We have
y = y = 6x - 5/x. Since 5x = 5x1/2, then
y' =
Transcribed Image Text:Find an equation of the tangent line to the curve at the given point. Illustrate by graphing the curve and the tangent line on the same screen. y = 6x - 5/x, (1, 1) Step 1 We can find the equation of a line by using the Point-Slope formula y - Yo = m(x - x). This means that we need to find the slope m of the line and a point (x Yn) on the line. We begin by finding the slope. The line tangent to y at (x, Yo) will have the slope m = f'(x,). We have y = y = 6x - 5/x. Since 5x = 5x1/2, then y' =
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