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A: F1 = 25 N due east F2 = 30 N due west F3 = 54 N due north F4 = 42 N due south
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A: Given,
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A: The force is the product of mass and acceleration. The unit of force is newton(N). Newtons 2nd law…
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A: F= 8.6*(10)^2 N θ = 15 ° G= 5.7*(10)^2 N ϑ= 112°
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Q: 7. Find the resultant of the forces: A= 150N, acting 30 degrees to left of the negative y-axis, and…
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A: Given F1=175N F2=195N F3=200N θ=30 α=60
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A:
Q: Find and plot the equillbrant for the following forces (use protractor and ruler) 4. Fa= 93.0 N at…
A: Solution: To plot the forces as vector quantity in the graph
Q: Find the vertical and horizontal component of Force. F=200 N
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Q: Question 1: If the magnitude of the resultant force is to be 500 N, directed along the positive Y…
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Q: Determine the resultant for the forces showing in figure (15) . at paint (0). Q 16 F Fig. (16)
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Q: Problem 3. Express the resultant of forces F, and Fz in component form. Fj = 80 lb y 30° 40 F = 130…
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A: F=3182+5632F=418.1 Nto find the direction,tanθ=318563θ=29.46° north to west.
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Q: Ex.3: determine the magnitude of forces FA and FB acting on each chain In order to develop a…
A: As given net force is in Y-axis so the net force on x - axis =0 so Fa*sin30o = Fb*sin30o Fa=Fb
Q: FT2 FT1 25° 200N
A: Free body diagram a
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A: F1→ = 120 N @70 degree above the positive x axis F1→ = 120 N × [ (cos70oi^) + (sin70oj^)]F1→…
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A: Given: Forces magnitude are: A=30 N at 45° B=25 N at 125° C=15 N at 220°
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A: solution is given by
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A: F1 =185 N F2 = 145 i + 120 j
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A: F1=530NF2=300NNow in vector form→F2 =300r2^→F1 =530r1^r2^ =-3i^ +4j^5r1^ =-4i^ -3j^5
Q: 250 N 400 N 30 300 N
A: Given:
Q: Question Select your answer. Which of the following component forces will yield alweaker resultant…
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Q: F=390 Ib 12 40 30 P=300 lb T=400 lb
A: The x and y component of the forces, are components along x-axis and y-axis. Fx = F Cos θ Fy = F…
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Q: Question 2: Contact Forces m,=5.0 kg m,=9.0 kg F = 109.2 Ny
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Q: Two horizontal forces F = 70NÎ + 20Nĵ and F = -30NÎ + 40Nj, are pulled a 12 body that is stuck in a…
A: Given forces are, F1→=70Ni^+20Nj^F2→=-30Ni^+40Nj^ Let the third force be F3→
Q: the positive 6. Find the angle that the tesultant of two forces: A= 150N, acting 60 degrees to left…
A: As requested by you, i am providing solution of question 6.
Q: angle
A:
Q: 1) Three forces act on a weight. Two of the force are at an angle of 100° to each other. One has a…
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Find and plot the equillbrant for the following forces (use protractor and ruler)
10. F10 = 82.0 N at 5.0 south of east
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- Two ropes are attached to a tree, and forces of and are applied. The forces are coplanar (In the same plane). (a) What is the resultant (net force) of these two force vectors? (b) Find the magnitude and direction of this net force.While sliding a couch across a floor, Andrea and Jennifer exert forces FA and FJ on the couch. Andrea’s force is due north with a magnitude of 130.0 N and Jennifer’s force is 32 east of north with a magnitude of 180.0 N. (a) Find the net force in component form. (b) Find the magnitude and direction of the net force. (c) If Andrea and Jennifer’s housemates, David and Stephanie, disagree with the move and want to prevent its relocation, with what combined forceFDS should they push so that the couch does not move?Two teenagers are pulling on ropes attached to a tree. The angle between the ropes is 30 . David pulls with a force of 400.0 N and Stephanie pulls with a force of 300.0 N. (a) Find the component form of the net force. (b) Find the magnitude of the resultant (net) force on the tree and the angle it makes with David’s rope.
- Find the resultant of the following forces using the polygon method and mathematical method.A = 30N at 45°B = 25N at 125°C = 15N at 220°Find and plot the equillbrant for the following forces (use protractor and ruler) 4. Fa= 93.0 N at 53.0 west of north 5. Fs = 65 N at 21.0 south of west 6. Fs= 102 N at 15.0 west of southFind and plot the equillbrant for the following forces (use protractor and ruler) 7. Fr 26 Nsouth 8. Fs = 77.0 N at 22.0 east of south 9. Fg = 51.0 N at 33.0 east ofsouth
- Find the magnitude and direction of the resultant of the two forces shown knowing that P = 600 N and Q = 450 N.Jerome and Michael, linebackers for South’s varsity football team, delivered a big hit to the halfback in last weekend’s game. Striking the halfback simultaneously from different directions with the following forces: FJerome = 1230 N at 53°FMichael = 1450 at 107° Determine the resultant force applied by Jerome and Michael to the halfback. (The directions of the two forces are stated as counter-clockwise angles of rotation with East.)Need help finding forces acting on A.
- Solve for the tension in the string. Does the tension change if the masses are shifted between the cart and the hanger?Brayden is pulling his little red wagon forward with a force of 230N by holding the handle at a 60o angle. His twin is pushing the wagon with a force of 300N. Find the magnitude and the direction of the resultant force on the wagon.Determine the resultant of the two forces shown.