Find current thru - j5 capacitive reactance use any method. -jsa 100/0 VA) 50 (1) 10/30A j42 1.026 - j0.465 A O 0.955 - jo.50 A O 0.706 + jo.353 A 0.938 - jo.536 A

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter7: Alternating Current, Power Distribution, And Voltage Systems
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Find current thru - j5 capacitive reactance use any method.
50
-js a
100/0' VA
52
1) 10/30'A
j4 2
1.026 - j0.465 A
0.955 - j0.50 A
0.706 + j0.353 A
0.938 - j0.536 A
Transcribed Image Text:Find current thru - j5 capacitive reactance use any method. 50 -js a 100/0' VA 52 1) 10/30'A j4 2 1.026 - j0.465 A 0.955 - j0.50 A 0.706 + j0.353 A 0.938 - j0.536 A
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