Chapter 9, Problem 9.017 I )-0.5 cos 2000r A, find the average power absortbed by each element ((a) 150-2 resistor, (b) 40-0 resistor, (c) source, (d) inductor, (e) capacitor) in the circuit in the figure below ww 40 0 150 60 mH 12.5F (a) (ь) W (c) W (d) (e)
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- An industrial load consisting of a bank of induction motors consumes 50 kW at a power factor of 0.8 lagging from a 220-V,60-Hz, single-phase source. By placing a bank of capacitors in parallel with the load, the resultant power factor is to be raised to 0.95 lagging. Find the net capacitance of the capacitor bank in F that is required.The average value of a double-frequency sinusoid, sin2(t+), is given by (a) 1 (b) (c) Zerofind the sinusodial expression for e if Va = 60sin(wt + 30°) Vb = 30sin (wt + 60°) Vc = 40sin (wt + 120°)
- Read A 70-Vac source has the following waveform. Determine:a. Vpkb. Vpk-pkc. Vrmsd. Periode. Frequencyf. Angular Velocityg. Phase Angleh. equation of the waveform (in time domain)i. the instantaneous voltage when t = 120 msj. the angle (1st occurrence) after t = 0 when the voltage is +80 Vk. the time (2nd occurrence) after t = 0 when the voltage is –10 VAnswers:a. 98.9949 Vb. 197.9899 Vc. 70 Vd. 100 mse. 10 Hzf. 20π rad/secg. 125.0876°h. v(t) = 98.9949sin(20πt + 125.0876°)i. -29.0880 Vj. 0.99959°k. 63.643 ms Give the solution for J and K ONLY ans (0.99959 degrees and 63.643 ms respectively)Determine the time-domain expressions for the line-to-line voltages vAB, vBC, and vCA. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degreesEx. 1844. Given a sinusoidal voltage source in series with R,L, and C. The sinusoidal voltage source has a frequency of 600 Hz. R=5 Ohms, L=2 milliHenry, C=4 microFarad, V=20sin(wt) volts. Solve for the capacitor steady-state phasor current and voltage. I(jw)=Aexp(jB), vc(jw)=Dexp(jE), IMPORTANT RESTRICTION: Express radian angles between [-pi/2,pi/2]. Solve for the capacitor steady-state time-domain current and voltage: i(t)=Fsin(wt+G), vc(t)=Hsin(wt+K) Ans: w,A,B,D,E,F,G,H,K all MKS units. ans:9
- Using the data in Table 1.1 convert the current I and source voltage Vs to RMS values. Then draw a plot of the power phasor diagrams at a frequency of 1000 Hz and another at a frequency of 8000 Hz. Determine the real power, the reactive power, and the apparent power in the RC circuit at those frequencies.Ex. 1844. Given a sinusoidal voltage source in series with R,L, and C. The sinusoidal voltage source has a frequency of 500 Hz. R=7 Ohms, L=8 milliHenry, C=6 microFarad, V=20sin(wt) volts. Solve for the capacitor steady-state phasor current and voltage. I(jw)=Aexp(jB), vc(jw)=Dexp(jE), Express radian angles between [-pi/2,pi/2]. Solve for the capacitor steady-state time-domain current and voltage: i(t)=Fsin(wt+G), vc(t)=Hsin(wt+K) Ans: w,A,B,D,E,F,G,H,K all MKS units. ans:9C = 93 | F = 14 | G = 39 | S = 85 For the sinewave, give the following six values. Must give the UNITS after each number. a. Vp (the peak voltage) b. Vpp (the peak-to-peak voltage) c. B (the DC bias or DC offset) d. T (the period) e. f (note that f will be a number of Hertz between 0 and 1 and your answer might have to be rounded OR you can choose to write it as a fraction), and f. θ, which is the phase shift in degrees in the expression Vpsin(ωt - θ) + B Vp = Vpp = B = T = f = θ =
- 1. For the following sinusoids, determine which one leads and by how much a. ?(?) = 10cos (4? − 60°) and ?(?) = 6sin (4? + 50°)b. ?ଵ(?) = 4cos (377? + 10°) and ?ଶ(?) = −20cos(377?)c. ?(?) = 13 cos(2?) + 5 sin(2?) and ?(?) = 15cos (2? − 11.8°)1. A 70-Vac source has the following waveform. Determine: a. Vpkb. Vpk-pkc. Vrmsd. Periode. Frequencyf. Angular Velocityg. Phase Angle h. equation of the waveform (in time domain)i. the instantaneous voltage when t = 120 msj. the angle (1st occurrence) after t = 0 when the voltage is +80 Vk. the time (2nd occurrence) after t = 0 when the voltage is –10 VAnswers:a. 98.9949 Vb. 197.9899 Vc. 70 Vd. 100 mse. 10 Hzf. 20π rad/secg. 54.9124°h. v(t) = 98.9949sin(20πt - 54.9124°)i. 29.0880 Vj. 108.8253°k. 66.8639 msGive the solution for K ONLY Ans: 66.8639 msA sinusoidal signal of 20V peak at 50 Hz is applied across a series combination of a resistor and inductor. If the impedance of the combination is Z = (10 + 5.03j)Ω, the power factor of this arrangement