Question
Asked Sep 18, 2019
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Find d/dx of 8csc^2(2x)cot(2x)

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Expert Answer

Step 1

Consider the given function:

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8csc2 (2x) cot (2x)

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Step 2

Now, find the derivative by using the product rule:

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d g dx dx dx then (Sesc2 (2.r))+8csc2(2.x)cot(2x) :(8ese2 (2x) cot(2x)cot (2x)(8cse' (2x)) dx

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Step 3

Now, use the formulas f...

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d (csce)=-cot0csc0 de d (cote)-csc20 de d ((g(x)) = f"'(g(x)) '(x) (chain rule) dx

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Tagged in

Math

Calculus

Derivative