Find e-t sin(v3t) 00 (a) (b) L-1 tan

Q: y = cos*x – sin*x

A: y = cos 4 x -  sin 4 x

Q: Can you help me with this problem step by step?

A: The logarithmic expression

Q: tan(e-2x) In(cos(e-2*)) dx 5 S е 2х

A: We have to find out

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A:

Q: Solve using implicit differentiation.  e^3x/ e^2y = sin y

A:

Q: Use the General Power Rule, Exponential Rule, or the Chain Rule to compute the derivative. y = (2…

A: Given function is   Differentiating both sides with respect to x, we get

Q: 4. S sin(tan-1 t) -dt 1+t2

A:

Q: Find the differential of the function y = x- sin x.

A: Given: y=x2-sinx

Q: = e* +cos x+-sinx+- 21 +x" Find general solution

A: we have to find the general solution of given differential equations

Q: cos(T/x5) dx 16

A: Given that: ∫cos(π/x15)dxx16

Q: y = e2* sin 2x + e3* cos 2x

A:

Q: Q3) Solve for (y) if: In(y-2)= In(sinx)-x

A: As per our guidelines we are supposed to answer only one question. Kindly second question as the…

Q: • y= cos(a' + x')

A:

Q: 4) Find the point(s) of inflection f(x)=(sinx)(e*)

A:

Q: Find ∫e^(2x)sin(2x)dx

A: Given: ∫e2xsin(2x)dx

Q: a- y= (cosx) (use logarithm differential)

A: To find dy/dx

Q: cos (5x-0.1) w(x) =- e*

A:

Q: dx (solve in two ways: let x = 6. x² /x² + 1 tan 0 or x =

A: Definition used -              Trigonometric substitution -                    When there a…

Q: Find the derivative.

A: given,         y=cos-1t-1-sec-1t

Q: use the General Power Rule, Exponential Rule, or the Chain Rule to compute the derivative. y =…

A: given y=cos9θ+41

Q: e sin(x²)dx <e-1. Jo Show that

A:

Q: sinh(3x) g(x) 3

A:

Q: | e3* sin(2x)dx

A:

Q: 14. The first derivative of y = arcsin4x is а. -4 b. -4 C. d. V1- 16x? VI- 4x2 V1– 16x? /1– 4x* -

A:

Q: (a) Find the derivative of the function g(x) = sin2 x + cos2 x (b) then use a trigonometric…

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Q: Find the first derivative Complete Solution.  1.) t=sinθtanθ

A:

Q: dx sin-1x +c using method V1 – x2

A: Given:

Q: Find dy Sor y -Sin X-/ xp

A: Given : y = sin-1 x-1x+1

Q: √ x³ e-x sin x dx 0

A: To solve the given integral  ∫0∞x3e-xsinxdx

Q: Find the first And 2nd derivative  F(x)= e^x sin4x

A:

Q: 4. (e) sinx-cos" xr sinx-

A: Since you have posted multiple questions, we will solve only first question for you. To getremaining…

Q: Solve the second derivative ду? for f(x) = tan-1

A: the given function f(x)=tan-1x2y2to find ∂2f∂y2

Q: Differentiate the function y = e - 4x  sin   5x

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Q: 3x-4 1. Y= Arctan 4

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Q: (e) l(x) := {/sec²(tan x) 3

A:

Q: 3. Find the derivative y'(x) implicitly. cos?x + cos²y = cos (2x + 2y)

A:

Q: 4 sin x-3 2. Find the first derivative of y =150xcos (10x)+ 9 In(J16-x)

A: use derivative of y

Q: If f(x) = sinh 2x − e2, find the exact numerical value of f"(ln 2).

A: Given : f(x) = sinh 2x − e2

Q: 11. In y = e" sin x

A:

Q: d'y by implicit differentiation. dx2 Given the equation 7y2 – x = 9, find

A: Given Implicit function is 7y2-x3=9

Q: dx ex sin2 (e

A:

Q: 1? sec?( sec-x)dx x/x2 -1 3

A: By using substitution we can the given integral

Q: e) y=sin(tanx) f) y = sin³ 7x

A:

Q: Find 1-x if y = cos-l dx 1+x²

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Q: x – sin-'(x). dx. /1 – x²

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Q: Find the second derivative of f(t) = ln(sin² (t)).

A: Given data: The given function is f(t)=ln(sin2(t)). The expression for the first derivative of the…

Q: Find the derivative: 1+e5 f(x) = = COS 1.

A: The given function is f(x)=cos1+e5x1-e8x

Q: Solve for the second derivative(y") of the following and simplify the final results. Show complete…

A: Given. ⇒4lntan-1x=1-y⇒y=1-4lntan-1x Taking derivative with respect to x, we get…

Q: Find the derivative of a. (e(sin2x))/[In(cos2x)]2

A: We have to find out derivative

Q: Find the first derivative of the function y = In[tan (pi/4 + x/2)

A:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.