Find EF in the trapezoid. A 5 E F 3x+5 7x+2 EF=

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A: Topic-Geometry

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A: The solution is given below

Q: A x+2 Find EF in the trapezoid E 4x 61 в A. O 21 В. 48 C. 9. D.O 36

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Q: A •B 3 E 5. D Given: M2ADC= 73° m24 = 45° m26 39° m25 = degrees m 2AEB = degrees 4.

A: Here we find the angle un given quadrilateral.

Q: Find EF in the trapezoid. x+4 A 6x E 73 C. В EF =

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A: Note: Hi there! Thank you for posting the question. As your question has more than 3 parts, we have…

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Q: Y; = bo + b,X1 + b2X2+ E¡ This is an example of a:

A: Note: Hi there! Thank you for posting the question. As you have posted multiple questions, as per…

Q: Find EF in the trapezoid. A 6 D E 3x+6 B 7x+3 C. EF =

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Q: ZE and ZFare supplementary. If m.E = (9x-38) and mZF=(2r+ 42), find mZF.

A:

Q: Find a value of c so that P(Z<c) = 0.71. a) O 0.45 b) O1.05 c) O 0.55 d) O 1.55 e) O -0.55

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Q: Solve: 4|x – 1| + 3 B OA<x<B Where A = Preview

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Q: b d+ 3a e + 36 f + 3c 2. If d f = 5, then h i is: e |9 h i -2a -26 -2c

A: by the row operation  i have solved the determinant

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Q: Find EF in the trapezoid. A6D E F 2x+7 5x+6 EF =

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Q: nd P(Z<c) = 0.8, then the value of c is %3D

A: Given that, Z is standard normal variate  hence mean=0  and standard deviation=1 P(z&lt;c)=0.8

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Q: b P+Q= (25) [e (1– (C+D)) –d (A+B)] vhere e (1 – (C+ D)) – d (A+ B) > 0. By adding (23)

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A: We have given that,  Let X be random variable from standard normal distribution with mean (μ) = 0…