Find equation of plane normal to line = = and pass through line x = y = z.
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A: We will use the basic knowledge of LU decomposition to answer this question.
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- Find the equations of the tangent plane and the normal line at point (1,1,-2) to surface z^2 = x^2-y^2+4Can point normal form of a plane have no y? Leaving only constant (x - constant) + constant (z - constant) = 0?Find parametric equations for the normal line to the surfacez=ln(3x2 +7y2 +1) at the point (0,0,0)
- Determine an equation of the rectifying plane to at x=1.find the equation of the tangent plane and normal line to the surface x^2+y^2-2xy-x+3y-z^2 at point (1,-1,2)find the frenet apparatus of curve 3u-u3 , 3u2 , 3u+u3 and Find equations of tangent, normal and binormal lines of this curve at the point 1 .
- Find equations of (a) the tangent plane and (b) the normal line to the surface 2(x−2)^2 + (y−1)^2 + (z−3)^2 = 10, at the point (3,3,5).The plane curve C is the part of y = x^4 that begins at the point (−1, 1) and ends at the point(1, 1). Evaluate the line integralFind a set of symmetric equations for the normal line to the surface xyz = 12 at the point (2, −2, −3).
- Find parametric equations for the normal line to the following surface at the indicated point.z = 4x2 − 5y2; (4, 5, -61)In your answer, use the given point and a unit direction vector that has a positive x-coordinate.The curve with parametric equationsx = t, y = 1 - cos t, 0 ≤ t ≤ 2πis called a sinusoid. Findthe point (x, y) where the slope of the tangent line is smallestDetermine the equation of the tangent plane and normal line to the surface at the given point. z=((x^2)/9) + ((y^2)/4) at the point (3, 2, 2)