DBTT CurveAn investigation of fracture behavior in BCCstructure metals is concerned with theductile to brittle transition temperature (DBTT)curve.10아DBTT curve8아3 different regions of:lower shelf, upper shelf and transition region60Upper shelf40Transition2아1: the brittle fracture surfaces consisting primarilyof cleavage facets (sharp).Lowpr sheft<-60-40 -202040Temperofure, CIl: ductile dimples or ductile tearing (T increase)Mix of ductile and brittle fracture1: the fracture surfaces become fully ductile. Thefracture surface appearsrelatively rough, dull and gray due to microvoid highest energy absorption due to extensiveformation and coalescence.This type of fracture surface provides theplastic deformation.Tpe No 5 CVam MetaEnergy absorbed,J * Find examples of metals (or other materials belongto:* Lower shelfUpper shelf* DBTT

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Answered: * Find examples of metals (or other…

Engineering

Mechanical Engineering

* Find examples of metals (or other materials belong to: Lower shelf Upper shelf * DBTT I

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A 3-cm-diameter penny-shaped slag inclusion is foundon the fracture surface of a very large component made of steelalloyed with Ni, Mo, and V. Could this defect have beenresponsible for the fracture if the stress acting on the component was 350MPa? The only material data available areCharpy results in the transition temperature regime whereimpact energy values of 7–10 ft-lb were reported. Be careful ofunits when you consult the KIC–CVN conversions.
The fracture of a brittle material is caused only by the maximum tensile stress in the material, and not the compressive stress. True or false? Explain why?
Why is the prediction of the tensile fracture of a brittle material is difficult to predict?
The stress intensity factor for a partial-through thickness crack is given bywhere a is the length of of crack through a wall thickness t. If the crack is 10 mm deep in a wall 20 mm thick determine whether the wall will support a stress of 190 MPa if it is made from steel with fracture toughness of 30 MPA m1/2
A component for an airerafl is made from an alyminum alloy that has a plane strain fracture toughness of 40 MPa mba. It has been determined thatfracture results at a stress of 365 MPa when the masimum internal crack length is 2.6 mm. For this component and alloy. compuie the stress leyel atwhich facture will occur for a crrical jnternal crack length of 4.0 mm
A cylindrical steel pressure vessel D-575 mm in diameter with a wall thickness of 5 mm is subjected to an internal pressure of 3 MN/m². Calculatea- the tangential and longitudinal stresses in the steel.b- To what value may the internal pressure be increased if the stress in the steel is limited to 80 MN/ m²?c-If the internal pressure were increased until the vessel burst, sketch the type of fracture that would occur
A polycrystalline metal has a plastic stress--strain curve that obeys Hollomon’s equation,σ = K εnDetermine n, knowing that the flow stresses of this material at 2% and 10%plastic deformation (offset) are equal to 175 and 185 MPa, respectively.
A bar with a square cross-section measuring 1.25 cm on a side is made of a material with yield strength of 310 MPa, and ultimate tensile strength of 515 MPa. Determine the maximum load the bar can withstand without fracture. Give your answer in N.
Your company designed a structure that includes analuminum plate for which you specified routine inspectionafter every 50,000 loading cycles. The NDT procedure thatis employed by the operator of the structure possesses aresolution limit of 1 mm. Through a mix-up, the inspectionteam calibrated their instrument to yield a crack resolutionlimit of 1 cm. No crack was found on this occasion, butunstable fracture took place following 34,945 additionalloading cycles in association with the development of anedge crack, oriented normal to the major stress direction.Injuries to clients of the operator resulted from the failure.The operator is being sued, but is trying to pass the blameonto your design team. Are there grounds for a lawsuitagainst you for improper design and inspection specifications, or against the operator based on improper inspectionprocedures? The key stress level fluctuates between 50 and100 MPa. The properties of the alloy are:KIC = 30 MPa √m , σys = 550 Mpa, E = 70 GPa, and…
A brass specimen of the circular cross-section is fractured at 159 kN force and the final length of the specimen at fracture is 51 mm. The fracture strength of the specimen is found to be 85 kN/mm2. The percentage of elongation of the specimen is 42 %. Determine the following 1-Initial Cross-sectional Area (in mm2) 2-The Diameter of the Specimen (in mm) 3-Initial Length of the Specimen (in mm)
Determine the critical crack length (mm) for a crack in a thick 2024-T6 alloy plate that has a fracture strength of KIC = 24.2 MPa (in) ^ 1/2 and is under a stress of 400 MPa.
Cortical bone is decidedly anisotropic in its fracture behavior. Crack propagation parallel to the long axis of a bone is much easier than perpendicular to the axis (i.e., “across” the bone). When fracture of a human tibia is measured in the parallel crack configuration, an average value of KIC = 3.95 MPa-m1/2 is found. Imagine that a hole is drilled through cortical bone in a direction perpendicular to the bone axis. The hole is intended to be used for insertion of a pin associated with repair of a nearby fracture. Imagine that in the hole drilling process, a semicircular crack is created emanating from the drilled hole aligned with the osteon cement lines (see Figure 6.22c for clarification). Assuming that the cortical bone is 3 mm thick, the modulus can be estimated as E = 20 GPa, and that during the surgery the worst-case tension strain that the bone will experience perpendicular to the crack is 2 x 10-3, what is the maximum tolerable crack radius to avoid fracture at the drilled…