Find in cylindrical components: -a) a unit vector at P(p = 5,9 = 53.13, z = -2), in the direction of F = pz cos p a, – pz sin o a, + pa a,%3Db) a unit vector at P parallel to azc) a unit vector at Q (p = 5, = -36.87, z = -2) parallel to axd) G = 2 a, – 4 ay + 4 a, at P.

Answered: Image /qna-images/answer/5f833608-2f7d-4bdb-8f1f-01ad0d67da9a.jpg

Find in cylindrical components: - a) a unit vector at P(p = 5,9 = 53.13, z = -2), in the direction of F = pz cos o a, – pz sin o a, + pa a, b) a unit vector at P parallel to a, c) a unit vector at Q (p = 5,9 = –36.87,z = -2) parallel to a, d) G = 2 ax – 4 a, + 4 az at P.

Find in cylindrical components: - a) a unit vector at P(p = 5,9 = 53.13, z = -2), in the direction of F = pz cos o a, – pz sin o a, + pa a, b) a unit vector at P parallel to a, c) a unit vector at Q (p = 5,9 = –36.87,z = -2) parallel to a, d) G = 2 ax – 4 a, + 4 az at P.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Solenoidal Vector Field

In Physics and Mathematics vector calculus attached to each point in a subset of space, there is an assignment of a vector in a field called a vector field.

Question

Find in cylindrical components: -
a) a unit vector at P(p = 5,9 = 53.13, z = -2), in the direction of F = pz cos p a, – pz sin o a, + pa a,
%3D
b) a unit vector at P parallel to az
c) a unit vector at Q (p = 5, = -36.87, z = -2) parallel to ax
d) G = 2 a, – 4 ay + 4 a, at P.

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