Find the 3rd degree Taylor polynomial T3 (x) centered at a 2 for the function f(x) = e"/5 e2/5 (x- 2) + T3 (x) = e2/5 + e2/5 e2/5 (x- 2)2 + 50 750 O T:(2) - e+(-2) + (- e? (x- 2) + (x - 2)2 + 50 (x – 2) 750 e2/5 (* - 2) + T3(x) = e2/5 + e2/5 e2/5 (x - 2)2+ 25 (x – 2) 125 e2/5 T3(x) = e2/5 + e2/5 e2/5 %3D 25 125 e2/5 E (z - 2) + T3 (x) = e2/5 + e2/5 (x- 2)2 + 50 e2/5 (x - 2)3 375

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Chapter6: Linear Systems
Section6.6: Partial Fractions
Problem 62E: Match the rational expression on the left with the correct partial fraction decomposition form on...
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Find the 3rd degree Taylor polynomial T3 (x) centered at a = 2 for the function f(x) = e"/
e2/5
(r- 2) +
T3 (x) = e2/5 +
e2/5
e2/5
(x- 2)2 +
50
(x - 2)3
750
T3 (x) = e? +
(*- 2) +
(x - 2)2 +
50
(x – 2)3
750
e2
e2/5
(* - 2) +
e2/5
(x - 2)2 +
T3 (x) = e2/5 +
e2/5
(x – 2)?
125
25
e2/5
T3 (x) = e2/5 +
e2/5
e2/5
25
125
e2/5
T3(x) = e2/5 +
e2/5
e2/5
(x - 2) +
(x-
2)2 +
375
(x – 2)3
50
Transcribed Image Text:Find the 3rd degree Taylor polynomial T3 (x) centered at a = 2 for the function f(x) = e"/ e2/5 (r- 2) + T3 (x) = e2/5 + e2/5 e2/5 (x- 2)2 + 50 (x - 2)3 750 T3 (x) = e? + (*- 2) + (x - 2)2 + 50 (x – 2)3 750 e2 e2/5 (* - 2) + e2/5 (x - 2)2 + T3 (x) = e2/5 + e2/5 (x – 2)? 125 25 e2/5 T3 (x) = e2/5 + e2/5 e2/5 25 125 e2/5 T3(x) = e2/5 + e2/5 e2/5 (x - 2) + (x- 2)2 + 375 (x – 2)3 50
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