Find the absolute extrema of the function on the closed interval. g(t) = t^2/t^2+5 {-2,-2} Minimum (t,y) = ( ) maximum (t,y) = ( ) smaller t value (t,y)= ( ) larger t value
Find the absolute extrema of the function on the closed interval. g(t) = t^2/t^2+5 {-2,-2} Minimum (t,y) = ( ) maximum (t,y) = ( ) smaller t value (t,y)= ( ) larger t value
Chapter3: Functions
Section3.3: Rates Of Change And Behavior Of Graphs
Problem 3SE: How are the absolute maximum and minimum similar to and different from the local extrema?
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Question
Find the absolute extrema of the function on the closed interval.
g(t) = t^2/t^2+5 {-2,-2}
Minimum (t,y) = ( )
maximum (t,y) = ( ) smaller t value
(t,y)= ( ) larger t value
Expert Solution
Step 1
I think the closed interval is [-2, 2] instead of [-2, -2]
Substitute t=-2 in the given equation
g(-2)=4/(4+5)=4/9=0.44 ....... (1)
Substitute t=2 in the given equation
g(2)=4/(4+5)=4/9=0.44 ...... (2)
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