Find the area of the shaded region. y =x+ - 2x3 1+ y = 0 -1 square units 2. 2.

Q: Find the area of the shaded region. y-2 C4, 2) O4, 2 A) 2 (B) n-2 D) n

A: The area of the region can be found by the following formula  Area =∫abydx Area =∫ab|f(x)-g(x)|dx…

Q: 3. Find the area, take the elements of the area parallel to the x-axis. y= 2x°- 3x-9x; y =…

A:

Q: Find the area of the shaded region. y = x3 - 4x <3,15) 3 A) 33 B) D)

A: We will solve the problem.

Q: Find the area A of the shaded region where b = 9. y = |x| + -b A =

A:

Q: Find the area of the shaded region shown below. YA y = -x? + 4x y = x2 - 2x

A:

Q: Find the area of the shaded region. 2 -1 square units y=x+ - 2x³ y=0

A:

Q: Find the area of the region enclosed by the graphs of: y? = 9 – x and x = 5. 32 A) 3 24 B) 3 16 C) 3…

A: The region is enclosed by the graphs ofy2=9-x and x=5

Q: Find the area of the shaded region. x = 2- y2 -2 2 11 A 10 - 3. 8. D. 3. 2.

A: The area of the Shaded Region: the shaded zone's area is computed by subtracting the area of a…

Q: y y= 4x y3= 2 y345– x

A:

Q: Find the area between the graph of y = 6x and the x-axis on the interval [-2, 2]. Write the exact…

A:

Q: Find the total area between the region and the x- axis. y = x3 – 3x? + 2x -1 sxs2

A: Consider the curves, y=x3-3x2+2x  ;       -1≤x≤2

Q: y=V.r+ 2 www r= 2

A:

Q: What is the area enclosed by the curves y= x° - 8x + 18x- 5 and y = x+ 5? A 10.667 в 11.833 14.583…

A:

Q: Find the area enclosed by the line y = x – 1 and the parabola y? = 2x + 6.

A: Given: The line is y = x-1 and the parabola is y2=2x+6   To determine: The area enclosed by the line…

Q: The area formed by the boundaries y=1, x=2, and y=e-x is closest to: a.1.586 b.2.746 c.1.135 d.3.542

A:

Q: What is the area of the shaded region? y = y = -2x*

A: We will take difference of both curves to find the area using integration.

Q: Find the area of the shaded region below. x= y? – 4y (-3, 3) x= 2y – y?

A:

Q: X = y 12 x = 216 / y? 12

A: Given curves are x=y   ...1x=216y2   ...2

Q: Find area bounded by the circle x? + y² = 25, the y-axis and the parabola y = 6x – x².

A:

Q: R] 280 A Area of the Sector:

A: I  am going to solve the given problem by using some simple calculus to get the required result.

Q: Find the area of the shaded region. The image is not to scale. x = -c y x=d- y? Consider c=6, d=7.…

A: If f(y) and g(y) are two continuous function  on the interval [a,b]  and f(y) ≥g(y) on a≤y≤b , then…

Q: Find the area of the shaded region. y (1, Зе) 8 6- y = 3 e* 4 2

A: We have given curves y = 3xex^2 and y=3ex And we have to find the area of shaded region

Q: ƒ(x)=3x² +6x−9

A:

Q: Find the surface area of the ball shown to the right. d=14 cm The ball has a surface area of cm?.

A: To find the surface area of the ball: Solution: We know that a ball is in spherical shape. The…

Q: Find the area of the shaded region. NOTE: Enter the exact answer. x = Y 20 1000 x = y2 20

A:

Q: Determine the area above y = 3x^2 + 6x - 9 and below the x-axis. 10 12 18 32

A: Given,  y=3x2+6x-9 And x axis  is y=0

Q: Find the area of the shaded region. NOTE: Enter the exact answer. y = x2 + 2 A =| y = x 2

A: We want to find the shaded area.

Q: Find the area of the shaded region. y = X - 3 (16,1) 16 (e,-3)

A: We first find where the curve cuts the x-axis

Q: Find the area of the shaded region. 15) y=-x4 y = x2 - 2x C) 2 76 D)- 15

A: From the given graph. Use the double integration method to calculate the bounded…

Q: Find the area of the shaded region. y y= xV4 x y=0 2 y= 0 -2 SQuare units 21

A:

Q: J. Find the area of shaded region in terms of T. 100 1. 2. acm 6 cm

A: The shaded area in both the figures are called as sectors of the circular figure. Let A be the area…

Q: Find the area of the shaded region. y X = y 6 x = 27 / y? 6

A: *to find:- Area, A under the closed region. *concept:- take horizontal elemental strip of length dx…

Q: y = 1/x2, y=9, x=6 Find the area of the region?

A:

Q: Find the area of the shaded region below. y = 3x - 3 y=-x + 3x +6 WCOLLEGE KL

A: We have to find the area under the curves.

Q: Find the area of the region enclosed by the graphs of: y? = x+5 and y2 = 3 - x. 32 A) 3 16 B) 3. 64…

A:

Q: Find the area of the shaded region. y 15 y = 7x-x² 10 (5, 10) 5 y= 2 x 4 6. Enhanced Feedhaclo

A: We can application integration in order to solve the given problem.

Q: (b) Find the area of the shaded region y=1 y=5-x^2

A: We have to compute the area bounded by the curve y=5-x2, the line y=1 and the y-axis. We will use…

Q: b) Find the area of the shaded region. 1) ii) アー =-y 2Fx=2-

A: 1. Required area is, ∫04x dx+∫04-14x dx=∫04x12 dx+14∫04x dx=x323204+14x2204=23432-0+148-0=238+2=223

Q: Find the area of the shaded region. y 3- 2 y = 1 -3 -1 1. 4 y = -1 -2 -3 Help? Read 3.

A: Here, the objective is to find the area of the shaded region.

Q: Find the area of the shaded region. NOTE: Enter the exact answer. y = = +4 A =

A: We have to find the area of the shaded region of the figure given below.  Cleary the shaded region…

Q: Determine the area enclosed by the curve r² = 4a²cos3θ a. 4a² b. 8a² c. 16a² d. a²

A: To find the area enclosed by the curve r2=4a2cos3θ

Q: Find the area of the shaded region. NOTE: Enter the exact answer. y = x² + 2 A y = x 2 3 ||

A:

Q: Find the area of the shaded region below. x = y? – 4y (-3, 3)

A:

Q: Find the area of the shaded region. square units y = x3 y = x + 6 8. -6 -5 -4 -3 -2 4 -IN

A:

Q: Find the area of the shaded region. y = x – 2 2+ y=V 1 2 3 4 | square units

A:

Q: yA y = 8x y = 9 – x? y =

A:

Q: Find the area of the region between y = 4x² and y = a? + 2.

A: Explained below

Q: Find the area of the shaded region. x = y 20 x = 1000 / y? 20

A: To find: (a) The area of a shaded region. (b) Use the shown in the figure to find the following:…

Q: Solve: Revolve about the (a) x-axis and (b) y-axis the area enclosed by y² = x and y = x³

A: The given area is enclosed by                         y2=x  and  y=x3

Q: Find the area of the region that is enclosed between y = 14x? – x³ + x and y = x2 + 41x. The area is

A: We need to find area enclosed under the curve.