Find the area of the shaded region. y y = x - 15 x 20 10 y= x (4, 4) -6 2 (-4, -4) - 10 - 20 A =

Q: Find the area of the region lying to the right of x = y? -4 and to the left of x = 2-y².

A: Use given curves x=y²-4  => y²=x+4 is a parabola  with axis of symmetry is (-4,0) And x=2-y²…

Q: Q5/ Find the area of the region in the first quadrant that is bounded above by y = √x and below by…

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Q: y x = y - 10 y (- ) 75 15 2 -30 -20 -10

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Q: Find the area of the shaded region. y = x - 32 y = -x4 Select one: A. 512 В. 2816 C. 256 D.

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Q: Find the area of the shaded region. (-11/4, 11/2) 10 y 8 x = y² - 6 y 6 4 -2 x = 5 y-y² 5

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Q: Find the area of the shaded region. y 2 x = y - 6 y=1 x= -4 -2 2 4 H y = -1 -3 2. 3.

A: Given two curves x=y2-6 and x=ey To find the area of shaded region bounded between y=-1 and y=1

Q: y y= 4x y3= 2 y345– x

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Q: Find the area of the shaded region. Ay y =x - 2x3 y = 0 -1 2 -1- square units 2.

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Q: A y y = x2 + 1 y = x -1 2

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Q: x² - y? + 2x = 1, y? – x = 4, and y = x - 2 %3D

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Q: Find the area of the region. y = 81 – x4 y 60 40 -2 4 2. 20

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Q: Find the area of the shaded region. ¡y = x² + 1 ... 5 y = x 2 A B D

A: Area of a bounded region by curves is given by ∬dydx.

Q: Find the area of the shaded region. 6) 8 10 x

A: Solution: The objective is to find the area of the shaded region

Q: Find the area of the shaded region. y x = y - 7 y = 1 x = ey -4 -8 -2 2 4 -6 y = -1 -2 -3 2.

A: We have to find the area with respect to y here. To find the area between x=e^y and x=y^2-7 we have…

Q: Find the area of the shaded region. y. 8- x= y-6y (-35/4, 7/2) -12 -10 -4 x=y-y

A: Please refer the attached image for complete solution.

Q: Find the area of the shaded region. Ans: 2 -0.31

A: The area under the Normal distribution curve represents the probability and the total area under the…

Q: Find the area of the shaded region. y=2x2+x-6 y=x2-4 W

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Q: Determine the area above y = 3x^2 + 6x - 9 and below the x-axis. 10 12 18 32

A: Given,  y=3x2+6x-9 And x axis  is y=0

Q: Find the area of the region below y = x² – 2x + 5 and above y 3 for 2 < a < 5.

A: To find area under the curve Shown below in shaded part

Q: Find the area of the shaded region. y x = y -8 -6 -4 -2 4 Hy=-1 2.

A:

Q: Find the area of the shaded region. y=x-4 y= /2x 2. 8. 10 x -4 2.

A: Given query is to find the area of tha shaded region.

Q: Find the area of the shaded region.

A: Given figure: And the equation of the curve is y=-x9-x2

Q: Q-3: Find the area of shaded region in the shape: y = x2- 6x + 5 3 5

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Q: nd the area of the shaded region. y x = y° - 10 y 10 (-75/4, 15/2) -30 - 20 -10 -5 x= 5 y- y

A: We have to find the  shaded area from the given

Q: Find the area of the shaded region.

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: Find the area of the region enclosed by the curves x+y 0 and x+6y 80. The area of the region…

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Q: Q5/ Find the area of the region in the first quadrant that is bounded above by y = √x and below by…

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Q: y = 1/x2, y=9, x=6 Find the area of the region?

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Q: Find the area of the shaded region. y 15 y=7x-x² 10 (5, 10) 5 y=2 x 4 8.

A: The area of the shaded region is, 125/6  the detailed solution is as follows below:

Q: Find the area of the shaded region. y 3| 2 x= y - 3 y = 1 X=

A: To find- Area of shaded region.

Q: Find the area of the shaded region. O Save y= 9 x- x 15 (7, 14) 10 5 y=2 x 2 4 8. 10 6. 20

A: To find the area of shaded region

Q: Find the area of the shaded region. y 3- 2 X = y' - 5 y = 1 x = e -6 -4 -2 2 4 y = -1 2

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Q: y = x? - x - 12, y = 0, x = -3, x = 3 y 10 10 10 10 5 -4 2 -4 -2 4 2 4 -5 - 10 10 -10 -10 Find the…

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Q: Find the area of the shaded region. x = y -4 y 2 -6 x = 3 y- y

A: From the given shaded region; Use the double integration method to find the area of the shaded…

Q: 5 т 2m 3 т

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Q: Find the area of the shaded region. x = y² - 4 -2 y 3 -3 y = 1 x = e² 2 y = -1 4 X

A: Given graph:-

Q: Find the area of : y: 4/x, y-4/x2, x=6

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Q: Find the area of the shaded region. y 3- 2 y = 1 -3 -1 1. 4 y = -1 -2 -3 Help? Read 3.

A: Here, the objective is to find the area of the shaded region.

Q: Determine the area of the shaded region in the graph below: y y=x²-1 d -1 X

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Q: Determine the area of the shaded region. 14r y=7x-x² 12 10 y=x 2 (6,6) 8

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Q: Find the area of the shaded region. square units y = x3 y = x + 6 8. -6 -5 -4 -3 -2 4 -IN

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Q: Find the area of the region. y = 81 – x4 y 80 60 40 - 4 -2 2 4 20

A: From the graph calculate the region for the integration.

Q: Find the area of the shaded region: y y = x - 15 x 20 10 y = x (4, 4) -6 2 4 6. (-4,-4) - 10 - 20

A: QUESTION-  Find the area of the shaded region

Q: 3. plot A (0, 1) B (4, 1) C (0, 4) find the area

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Q: y = 7x2,    y2 =  1/7x Find the area

A: To find the area bounded by the curves y = 7x2,    y2 =  17x

Q: Find the area of the shaded region. y 15 y=7x-x² 10 (5, 10) y=2 x 4 8.

A:

Q: Find the area of the shaded region. r = 4 + 3sin(0) 6- y -6 -2 6. 2.

A: Given that: r=4+3sin(θ)

Q: Find the area of the shaded region. y x = y - 4 y 15 5 4'2 2 -6 -5 -4 3 -2 X= y-y -2 -4 -6F

A: Given, The right function   x = y -y2  and left function     x = y2 - 4y Point of intersection of…

Q: Find the area of the region enclosed by the curves x+ y =0 and x+6y = 20. The area of the region…

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Q: Find the area of the region that is enclosed between y = 14x? – x³ + x and y = x2 + 41x. The area is

A: We need to find area enclosed under the curve.

Optimization

Optimization comes from the same root as "optimal". "Optimal" means the highest. When you do the optimization process, that is when you are "making it best" to maximize everything and to achieve optimal results, a set of parameters is the base for the selection of the best element for a given system.

Integration

Integration means to sum the things. In mathematics, it is the branch of Calculus which is used to find the area under the curve. The operation subtraction is the inverse of addition, division is the inverse of multiplication. In the same way, integration and differentiation are inverse operators. Differential equations give a relation between a function and its derivative.

Application of Integration

In mathematics, the process of integration is used to compute complex area related problems. With the application of integration, solving area related problems, whether they are a curve, or a curve between lines, can be done easily.

Volume

In mathematics, we describe the term volume as a quantity that can express the total space that an object occupies at any point in time. Usually, volumes can only be calculated for 3-dimensional objects. By 3-dimensional or 3D objects, we mean objects that have length, breadth, and height (or depth).

Area

Area refers to the amount of space a figure encloses and the number of square units that cover a shape. It is two-dimensional and is measured in square units.