Find the complexity of the below program: for (i=0; i<=n-1; i++){ for (j=i+1; j<=n-1; j++){ loop body }
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- The time complexity for the loop with elementary operations: Assuming these operations take unit time for execution. This unit time can be denoted by O(1). If the loop runs for N times without any comparison. Below is the illustration for the same: // C++ program to illustrate time // complexity for single for-loop #include <bits/stdc++.h> using namespace std; // Driver Code int main() { int a = 0, b = 0; int N = 4, M = 4; // This loop runs for N time for (int i = 0; i < N; i++) { a = a + 10; } // This loop runs for M time for (int i = 0; i < M; i++) { b = b + 40; } cout << a << ' ' << b; return 0; } Create an ipo, then analyze it until you get a big O1. Determine the problem to be solved with a particular algorithm2. Develop algorithms (in the algorithm there must be at least 1 iteration operation, 1 selection operation and several assignment operations)3. Algorithm analysis4. Determine the…C programing Draw the recursion tree to find out the value of f(5)int f(int n){int ans;int i;if(n<3)return n;ans = f(n/2);for(i=0; i<n; i++)ans += f(i);return ans;}Draw the recursion trace for the following algorithm, which is written in a pseudocode style: method6(int x, int y) { // returns integer if y=0, then return 1; else { int w = method6(x, y/3); // y/3 is integer division int z = w * x; if y is even, then z = z * 2 + 1; y = y + 1; end of if return z } // end of else
- Simplistic Algorithms with a Fixed Number of Integers (with C++) Write a program that takes three integers and outputs them in reverse order of how they were entered. For example, if the user enters 39, 51, 16 then the program should output 16, 51, 39.What is the worse-case complexity scenario for the following snippets of code? Please show the breakdown of your calculations.Two loops in a row: A nested loop in which the number of times the inner loop executes depends on the value of the Outer loop index. For ( I = 0; I < N; i++) { For ( j = N; j > I; j- - ) { Sequence of statements } }Modern programming languages would automatically transform a non-tail-recursive function to its equivalent tail-recursive implementation or loop variant which is more efficient in terms of both space and time, compared to a non-tail-recursive equivalent function. Give explanations as to how space efficiency is obtained. Give explanations as to how time efficiency is obtained.
- Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n2) and runtime should be under 1 second. Apply dynamic programming. Do not use recursion. Make sure ALL test cases return expected outputs. Output FormatFor each query, output one line containing an integer Dn. The number must be output mod (109 + 7). Sample Input 0:501234 Sample Output 0:10129 Edge Case: (to test against runtime and timeout error)300000 (number of queries)300000300000300000300000...and so on until there are 300,000 of them The actual code: def solve(n): MOD = 1000000007 # compute and return answer here q = int(input().rstrip()) outs = [] for i in range(q): n = int(input().rstrip()) outs.append(solve(n)) print("{}".format("\n".join(list(map(str,outs)))))Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply dynamic programming. Do not use recursion/memoization. Make sure ALL test cases return expected outputs. Sample Input 04 412340123 Sample Output 013715 Explanation 0You are given the sequence 1,2,3,4.F0 = A0 = 1F1 = A1 + F0 = 2 + 1 = 3F2 = A2 + F1 + F0 = 3 + 3 + 1 = 7F3 = A3 + F2 + F1 + F0 = 4 + 7 + 3 + 1 = 15 The actual code def solve(k,a): MOD = 1000000007 # compute and return answer here q, n = list(map(int,input().rstrip().split(" ")))a = [int(input().rstrip()) for i in range(n)]outs = []for i in range(q): k = int(input().rstrip()) outs.append(solve(k,a))print("{}".format("\n".join(list(map(str,outs)))))Can you write a recursive c program that takes as an input a total of N integers and prints every subtotal that has a sum equal to zero (if exists). Also mention its complexity ex. input:N = {-10, -3, 1, 2, 4, 6) output: {-10, 4, 6}, {-10, -3, 1, 2, 4, 6}, {-3, 1, 2}
- Develop two algorithms, one based on a loop structure and the other on a recursive structure, to print the daily salary of a worker who each day is paid 2.5 times the previous day’s salary (starting with one penny for the first day’s work) for a 30-day period. What problems relating to number storage are you likely to encounter if you implement your solutions on an actual machine?This is a MATLAB Coding problem: Implement a recursive function, called count, that takes two inputs, an array of integers and target integer. count should search the array for the target integer and return the number of occurrences of the target integer in the array. For example: disp(count([1, 2, 4, 1, 2, 1], 1)) % Generates 3disp(count([1, 2, 4, 1, 2, 1], 2)) % Generates 2disp(count([1, 2, 4, 1, 2, 1], 4)) % Generates 1disp(count([1, 2, 4, 1, 2, 1], 9000)) % Generates 0Generate a graph of performance improvement for code below. Tip: Figure 5.17 in the textbook provides an example of a graph depicting performance improvements associated with loop unrolling. code: //normal code int main() { int n, sum=0; n=50; int a[50]; { for(int i=0; i<n; i++) { sum= sum +a[i]; } printf("sum is %d", sum); return 0; } //with unrolling int main() { int n, sum=0; n=50; int a[50] for(int i=0; i<n; i+=10) { scanf("%d", &a[i]); } sum= sum + a[0]; sum= sum + a[1]; sum= sum + a[2]; sum= sum + a[3]; sum= sum + a[4]; sum= sum + a[5]; sum= sum + a[6]; sum= sum + a[7]; sum= sum + a[8]; sum= sum + a[9]; printf("sum is %d", sum); return 0; }