Write a Java recursive method to print Fibonacci series of n terms. Fibonacci series starts with 0 and 1, and the sum of previous two numbers is the next number of the series. For instance, 0, 1, 1 (0 + 1), 2 (1 + 1), 3 (1 + 2), and so on. Sample input:  10 Sample output: 0 1 1 2 3 5 8 13 21 34

Write a recursive form of the following: 0! = 1 n! = n * (n - 1)!

Python recursively trace the code

Given below is a recursive algorithm to compute r". The input r can be any real number. The input n is assumed to be a non-negative integer. Exponent ( r, n) #Input: Real number r and a non-negative integer n. +Output: r If (n-0), return (1) p: Exponent ( ? ) Return ( rp) //The base case 7/The recursive call What missing input values should be used in the recursive call? O (r, n) O (r, n-1) O (r-1, n) O (r-1. n-1)

python   the code to be done is already pointed out

using C++ program.

Write a short recursive Java method that takes a character strings and outputs its reverse. For example, the reverse of 'pots&pans' would be 'snap&stop'.

Using recursion, write a Java program that takes an input ‘n’ (a number) from a user to calculate and print out the Fibonacci using the following modified definition:   F(N) = 1                                                    if n = 1 or n = 2         = F((n+1)/2)2 + F((n-1/2)2           if n is odd         = F(n/2 + 1)2 – F(n/2 – 1)2         if n is even                                     Your solution must implement recursion to receive points for this question.

Write a java program that uses a recursive algorithm to print all the valid (properly closed and open brackets) combinations of a number of parentheses taken from the user. For example your program should behave similar to the below: Enter a number  your input is : 3 output :((())), ( () () ), (()) (), () (()), () () ()

Java: Is there a way to solve the following using Recursion instead of while and for-loops?