Find the derivative at each critical point and determine the local extreme values. y = x(1 - x) Select one: А. Critical Pt. derivative Extremum Value x= -0.58 10 local max -0.77 x= 0.58 local min 0.38 В. Critical Pt. derivative Extremum Value x= 0.58 local max 0.38 x = -0.58 local min -0.38 C. Critical Pt derivative Extremum|Value x= 0.58 x = -0.58 local max -0.77 local min 0.38 D. Critical Pt. derivative Extremum/Value x = -0.58 local max 0.38 x= 0.58 local min -0.77

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Find the derivative at each critical point and determine the local extreme values.
y = x(1 - x)
Select one:
А.
Critical Pt. derivative Extremum Value
local max -0.77
x= -0.58
x = 0.58
local min
0.38
В.
Critical Pt. derivative Extremum Value
x= 0.58
x = -0.58
local max
0.38
local min -0.38
C.
Critical Pt. derivative Extremum Value
x = 0.58
x = -0.58
local max -0.77
local min
0.38
D.
Critical Pt. derivative Extremum/Value
x= -0.58
local max
0.38
x = 0.58
local min -0.77
Transcribed Image Text:Find the derivative at each critical point and determine the local extreme values. y = x(1 - x) Select one: А. Critical Pt. derivative Extremum Value local max -0.77 x= -0.58 x = 0.58 local min 0.38 В. Critical Pt. derivative Extremum Value x= 0.58 x = -0.58 local max 0.38 local min -0.38 C. Critical Pt. derivative Extremum Value x = 0.58 x = -0.58 local max -0.77 local min 0.38 D. Critical Pt. derivative Extremum/Value x= -0.58 local max 0.38 x = 0.58 local min -0.77
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