Find the differential dy: y = In(sec² ( 3ª²–20+5 312-2x+5 O (E) None of the choices dy = 2 (x – 1) In(3) tan(3*²–2a+5 ) dx O dy = 4 (x – 1) In(3)3²-2=+5 tan(3*-2z+5 dx O dy = (x – 1) In(9)3²²–2r+5 tan(3*-2x+5 dx dy = 2 (x – 1) In(3)3=²-2»+5 tan(3 2-2x+5 dx

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