Integrate using Partial Fraction Decomposition x2dx(x+2)3In |x + 2| +4x+6+ C(x+2)=In |x + 21 –4x+6+ C(x+2)=Option 1Option 2송n lx + 2| +4x+6+ CIn Ix + 2| –4x+6+ C(x+2}=(x+2)=Option 3Option 4Other:None of the above

Answered: Image /qna-images/answer/e6f88591-906f-4a40-b789-1430868b9835.jpg

Answered: x2 (x+2)³ In Ix + 21 + 4x+6 4x+6 (x+2)=…

x2 (x+2)³ In Ix + 21 + 4x+6 4x+6 (x+2)= In |x + 2| – (x+2)= +C Option 1 Option 2 ihk+ 21- 4x+6 In lx + 21 + 4x+6 (x+2)= (æ+2)= Option 3 Option 4 Other:

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter1: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 50RE

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Question

Integrate using Partial Fraction Decomposition

x2
dx
(x+2)3
In |x + 2| +
4x+6
+ C
(x+2)=
In |x + 21 –
4x+6
+ C
(x+2)=
Option 1
Option 2
송n lx + 2| +
4x+6
+ C
In Ix + 2| –
4x+6
+ C
(x+2}=
(x+2)=
Option 3
Option 4
Other:
None of the above

With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.

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