Find the directional derivative of the function

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.3: Vectors
Problem 60E
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Find the directional derivative of the function at the given point in the direction of the vector v. 

11-17 Find the directional derivative of the function at the given
point in the direction of the vector v.
11. f(x, y) = 1 + 2x/y, (3,4), v= (4, –3)
12. f(x, у) — In(x? + у?), (2, 1), v3 (-1,2)
||
13. д(р, q) — р* - р'g, (2, 1), v %3Di+3j
14. g(r, s) = tan"(rs), (1, 2), v = 5i + 10j
15. f(x, y, z) = xe' + ye² + ze*, (0,0, 0),
(5, 1, –2)
|
(16. f(x, y, z) = Vxyz, (3, 2, 6), v=(-1,–2, 2)
17. д(х, у, 2) — (х + 2у + 32)3/2, (1, 1, 2), v %3D 2j — k
||
Transcribed Image Text:11-17 Find the directional derivative of the function at the given point in the direction of the vector v. 11. f(x, y) = 1 + 2x/y, (3,4), v= (4, –3) 12. f(x, у) — In(x? + у?), (2, 1), v3 (-1,2) || 13. д(р, q) — р* - р'g, (2, 1), v %3Di+3j 14. g(r, s) = tan"(rs), (1, 2), v = 5i + 10j 15. f(x, y, z) = xe' + ye² + ze*, (0,0, 0), (5, 1, –2) | (16. f(x, y, z) = Vxyz, (3, 2, 6), v=(-1,–2, 2) 17. д(х, у, 2) — (х + 2у + 32)3/2, (1, 1, 2), v %3D 2j — k ||
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