Q: Find the equation of tangent and normal to the curve y= 3x2 - 4x+5 at (– 1, 12)
A: Given the equation y=3x2−4x+5
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Q: Find the equation of the tangent and the normal to the curve y=5x4 at the point (1,5)
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A: On solving this we will get
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A: The above question is answered below
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Q: find the equation of tangent and normal to the curve √ x-√ y=1 at (9,4)
A: find the equation of tangent and normal to the curve √ x-√ y=1 at (9,4)
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A: we have to find an equation of the form y=f(x) for a curve with x-intercept 2 whose tangent line at…
Q: Find the slope of the tangent line to y=3x at x=0. Show all work please
A: The given equation is y = 3x.Differentiate with respect to x on both sides,(dy/dx) = 3x ln(3).
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Q: Find an equation of normal line to the curve y = Vx that is parallel to the line 2x+y = 4.
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Q: Find the slope of the tangent line to the curve (a lemniscate) 2(z + v²) = 25(z² - y³) at the point…
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Q: Find an equation of the tangent line to the curve y = 2x2 +3 that is parallel to the line 82 – y + 3…
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Q: Find the slope of the tangent line to the curve 3x + læy + 3y° = - 199 %3D at the point (1, – 4).
A: we know that the slope of the tangent to the given curve is =dy/dx.
Q: Find the equation (in terms of x and y) of the tangent line to the curve r=4sin2θ at θ=π/3. y=?
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Q: Find the equation of the tangent line and normal line to the curve: 2. x2 + 2xy = y3 at the point…
A: Firstly, we find dy/dx by differentiating both sides with respect to x
Q: 3. Determine the equation of the tangent plane and normal line to 2xz + y²z³ = x + 5 at (1,0,3)
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Q: Find equations of the tangent and normal line to the curve y = 3Vx – 2Vx4 at (1,1) |
A: NOTE: Refresh your page if you can't see any equations. . to find the slope take the derivative
Q: What is the slope of the tangent line to a curve with parametric equations of x= 2t+1 and y= 3t-1? *
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Q: Find point(s) on the curve y = x3 – 5x2 + 6x + 1 where the tangent line is horizontal.
A: Find the points where the tangent is horizontal
Q: Find the equations of the tangent and the normal lines to the curve x5 + y5 = 4 x2y2 at the point…
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Q: Find an equation of the tangent line to the curve y = x/x that is parallel to the line y = 6 + 3x. y…
A: The given question has been solved in detail
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A: Product of slopes of two perpendicular lines is -1.
Q: Find equations of the tangent and normal line to the curve y = V3 +x² at x = 1.
A: Recall: slope-point intercept form: y-y1=m(x-x1) ; where 'm' is the slope and (x1,y1) given points.…
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Q: Determine the equations of the tangent and normal to the curve y=2xex at (0,0)
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Q: Find the equation of normal to the curve y = 2x – 4x² +x- 6 at point (2,–4)
A: Given y=2x3-4x2+x-6 and point is P(2,-4)We need to find the slope i.e. y'dydx=ddx(2x3-4x2+x-6)We…
Q: Find the tangent line at (-1,3) to the curve y* – 2x*y' - 27=0.
A: Given, The equation of the curve y4 -2x2y3 -27 = 0 We have to find the tangent line at -1, 3 .…
Q: Find the points on the curve y = 2x3 + 3x2 − 12x + 6 where the tangent line is horizontal.
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Q: i.) Find the tquation of the tangent line to the curve y= 2+4x- x° at the point P(-1,-1)
A: "Since you have asked multiple question, we will solve the first question for you. If you want any…
Q: Find the equations of the tangent and the normal at the point indicated. y = x2 - 2x at its…
A: Given that - y = x2 - 2x at its points of intersections with the line y = 3
Q: At what point on the curve y = 4 + 2ex − 4x is the tangent line parallel to the line 4x − y = 9?…
A: Given, y=4+2ex-4x First, find the slope of tangent line parallel to the line 4x-y=9 Find the point…
Q: calculate the slope of the tangent line to the curve 3x3y2-2y3=-4 at the point (1,2)
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Q: Find the points on the curve y=2x^3 + 3x^2 -12x +3 where the tangent line is horizontal. (x,y) =…
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Q: 2. What is the slope of the line tangent to the curve 8x3-y²=4 at the point (1,-2)? CAL normal line…
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Q: Find the equation of the tangent line to the curve y = 2 In(x³ – 26) at the point (3, 0). y =
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Q: Find the tangent line to the curve ry = a +y+1 at (3,2)
A: Given data: The expression for the given curve is xy=x+y+1. The given point is (a,b)=(3,2).…
Q: Calculate the gradient of the tangent line to the curve y3 - x3 -xy = 1at the point (-1,0).
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Find the equation of a line normal to the curve x^2=16y at (4,2).
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