Find the error in the following work. d 2x+5 2 dx x². - 1 (2x+5)(2x)-(x²-1)2 (x²-1)² 4x²+10x-2x²+2 2 (x²-1)2 2x²+10x+2 (x²-1)² Choose the correct answer. ○ A. In the first step, the numerator should be (x² - 1) (2x+5)-(2x)2. OB. In the first step, the numerator should be (x²-1) 2-(2x+5)(2x). OC. In the last step, the numerator should be 2x² - 10x+2. OD. In all three steps, the denominator should be (2x+5)².

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter6: Fractions
Section6.4: Least Common Denominators
Problem 13E
Question
Find the error in the following work.
d 2x+5
dx
2
x 1
-
(2x+5)(2x)-(x²-1)2
(x²-1)²
4x²+10x-2x²+2
2
2
2
(x²-1)²
2x²+10x+2
(x²-1)²
Choose the correct answer.
○ A. In the first step, the numerator should be (x² -1) (2x+5)-(2x)2.
2
○ B. In the first step, the numerator should be (x² - 1) 2-(2x+5)(2x).
○ C. In the last step, the numerator should be 2x² - 10x+2.
○ D. In all three steps, the denominator should be (2x+5)².
Transcribed Image Text:Find the error in the following work. d 2x+5 dx 2 x 1 - (2x+5)(2x)-(x²-1)2 (x²-1)² 4x²+10x-2x²+2 2 2 2 (x²-1)² 2x²+10x+2 (x²-1)² Choose the correct answer. ○ A. In the first step, the numerator should be (x² -1) (2x+5)-(2x)2. 2 ○ B. In the first step, the numerator should be (x² - 1) 2-(2x+5)(2x). ○ C. In the last step, the numerator should be 2x² - 10x+2. ○ D. In all three steps, the denominator should be (2x+5)².
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