Find the following probability for the standard normal random variable z. e. P(z 20) f. P(-2.54 szs1.35) g. P(z> - 2.15) h. P(z< 2.15) a. P(z>1.15) b. P(z< - 1.83) c. P(0.01szs2.63) d. P(-1.981.15) = .125 (Round to three decimal places as needed.) b. P(z< -1.83) = .034 (Round to three decimal places as needed.) c. P(0.01szs2.63) = .492 (Round to three decimal places as needed.) d. P(-1.98 sz< - 0.64) =|(Round to three decimal places as needed.)
Find the following probability for the standard normal random variable z. e. P(z 20) f. P(-2.54 szs1.35) g. P(z> - 2.15) h. P(z< 2.15) a. P(z>1.15) b. P(z< - 1.83) c. P(0.01szs2.63) d. P(-1.981.15) = .125 (Round to three decimal places as needed.) b. P(z< -1.83) = .034 (Round to three decimal places as needed.) c. P(0.01szs2.63) = .492 (Round to three decimal places as needed.) d. P(-1.98 sz< - 0.64) =|(Round to three decimal places as needed.)
Chapter8: Sequences, Series,and Probability
Section8.7: Probability
Problem 11ECP: A manufacturer has determined that a machine averages one faulty unit for every 500 it produces....
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Transcribed Image Text:Find the following probability for the standard normal random variable z.
a. P(z>1.15)
b. P(z< - 1.83)
c. P(0.01<zs2.63)
d. P(-1.98<z< - 0.64)
e. P(z20)
f. P(-2.54 sz<1.35)
g. P(z2 - 2.15)
h. P(z< 2.15)
a. P(z>1.15) = .125 (Round to three decimal places as needed.)
b. P(z< - 1.83) = .034 (Round to three decimal places as needed.)
c. P(0.01szs2.63) = .492 (Round to three decimal places as needed.)
d. P(-1.98<z< - 0.64) =|| (Round to three decimal places as needed.)
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