Find the general solution of Зx(у - 4) x2 + 3 1+ (x² + 3)3 1- (x² + 3)3 a) Oy = 2 + 2C(x2 + 3)6 b) Oy = 1 - C(x² + 3)6 2 – 2(x? + 3)3 с) Оу 1 + (x² + 3)³ 1- С( + 3)6 1 + C(x² + 3)6 d) Oy = 2 + 2(x² + 3)³ e) Oy = 1- (x2 + 3)3 1+ C(x² + 3)6 1- С(* + 3)6 f) Oy = g) None of the above.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.5: The Binomial Theorem
Problem 16E
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Find the general solution of
Зx(у - 4)
x2 + 3
1+ (x² + 3)3
1- (x² + 3)3
a) Oy =
2 + 2C(x? + 3)6
1- С(x2 + 3)6
b) Oy =
2 – 2(x2 + 3)3
y =
1+ (x² + 3)3
1- C(x² + 3)6
1+ C(x² + 3)6
d) Oy =
2 + 2(x? + 3)3
y =
1- (x2 + 3)3
1+ C(x² + 3)6
1- С(? + 3)6
f) Oy =
g) O None of the above.
Transcribed Image Text:Find the general solution of Зx(у - 4) x2 + 3 1+ (x² + 3)3 1- (x² + 3)3 a) Oy = 2 + 2C(x? + 3)6 1- С(x2 + 3)6 b) Oy = 2 – 2(x2 + 3)3 y = 1+ (x² + 3)3 1- C(x² + 3)6 1+ C(x² + 3)6 d) Oy = 2 + 2(x? + 3)3 y = 1- (x2 + 3)3 1+ C(x² + 3)6 1- С(? + 3)6 f) Oy = g) O None of the above.
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