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Find the heat of reaction and explain what happen to it. Calculate the ∆H of reaction for: C3H8 (g) + 5O2 (g) => 3CO2 (g) + 4H2O (l) The values of ∆H of reaction are as follows: C3H8 (g) = -103.95 kJ/mol CO2 (g) = -393.5 kJ/mol H2O (g) = -285.8 kJ/mol Topic: Enthalpy of Reaction

Find the heat of reaction and explain what happen to it. Calculate the ∆H of reaction for: C3H8 (g) + 5O2 (g) => 3CO2 (g) + 4H2O (l) The values of ∆H of reaction are as follows: C3H8 (g) = -103.95 kJ/mol CO2 (g) = -393.5 kJ/mol H2O (g) = -285.8 kJ/mol Topic: Enthalpy of Reaction

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter10: Entropy And The Second Law Of Thermodynamics
Section: Chapter Questions
Problem 10.94PAE
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Find the heat of reaction and explain what happen to it.

Calculate the ∆H of reaction for: C3H8 (g) + 5O2 (g) => 3CO2 (g) + 4H2O (l)

The values of ∆H of reaction are as follows:
C3H8 (g) = -103.95 kJ/mol
CO2 (g) = -393.5 kJ/mol
H2O (g) = -285.8 kJ/mol

Topic: Enthalpy of Reaction

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