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Find the IHD and fragment/cleavage
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- The 1H- and 13C-NMR data of an ester of molecular formula C6H10O2 are given below. Also shown are the COSY and HETCOR NMR spectra of the ester. Draw the structure of the ester, explaining how you reach your conclusion. 1H-NMR: 7.20-6.90 (1H), 5.85 (1H), 4.16 (2H), 1.88 (3H), 1.31 (3H) ppm 13C-NMR: 166.7, 144.5, 123.0 , 60.2, 18.0, 14.3 ppmFollowing is a 1H-NMR spectrum of 2-butanol. Explain why the CH2 protons appear as a complex multiplet rather than as a simple quintet.The carbonyl absorption of an amide typically occurs in the 1630–1680 cm-1 range, while the carbonyl absorption of an ester occurs at much higher wavenumber, typically 1735–1745 cm-1. Account for this difference.
- 3 The 1H- and 13C-NMR data of an ester of molecular formula C6H10O2 are given below. Also shown are the COSY and HETCOR NMR spectra of the ester. Identify the ester, explaining how you reach your conclusion. 1H-NMR: 7.20-6.90 (1H), 5.85 (1H), 4.16 (2H), 1.88 (3H), 1.31 (3H) ppm 13C-NMR: 166.7, 144.5, 123.0 , 60.2, 18.0, 14.3 ppmI have an NMR spectrum. There are 5 peaks. There is a doublet at 9.6 ppm (integrates to 2H) where aldehydes usually arise, don't know why there is a doublet. There is another doublet at 6.8 ppm, again integrating to 2H. There is a singlet at 4.5 ppm, integrating to 1H. There is a quartet at 3.4 ppm integrating to 2H, and lastly there is triplet at 1.2 ppm integrating to 3H. i recofnize the ethyl group but don't understand the peak at 9.6 unless it is not an aldehyde.What is the structure for this H NMR, C6H14O HDI = 0
- Carboxylic acids (RCO2H) react with alcohols (ROH) in the presence of an acid catalyst. The reaction product of propanoic acid with methanol has the following spectroscopic properties. Propose a structure. MS: M+=88 IR: 1735 cm-1 1H NMR: 1.11 (3 H, triplet, J=7 Hz); 2.32 (2 H, quartet, J=7 Hz); 3.65 (3 H, singlet) 13C NMR: 9.3, 27.6, 51.4, 174.63-Bromo-1-phenyl-1-propene shows a complex NMR spectrum in which the vinylic proton at C2 is coupled with both the C1 vinylic proton (J = 16 Hz) and the C3 methylene protons (J = 8 Hz). Draw a tree diagram for the C2 proton signal, and account for the fact that a five-line multiplet is observed.A 13C NMR spectrum of commercially available 2,4-pentanediol, shows five peaks at 23.3, 23.9, 46.5, 64.8, and 68.1 . Explain.
- Propose structures for molecules that meet the following descriptions. Assume that the kinds of carbons (1, 2, 3, or 4) have been assigned by DEPTNMR. a) C6H12O;IR: 1715 cm-1; 13C NMR: 8.0 (1), 18.5 (1), 33.5 (2), 40.6 (3), 214.0 (4) b) C5H10O; IR: 1730 cm-1; 13C NMR: 22.6 (1), 23.6 8 (3), 52.8 8 (2), 202.4 8 (3) c) C6H8O; IR: 1680 cm-1; 13C NMR: 22.9 (2), 25.8 8 (2), 38.2 (2). 129.8 8 (3), 150.6 8 (3), 198.7 (4)What is the standard solvent in both 1H and 13C NMR? A. (CH3)4Si B. D2O C. CDCl3 D. C6H6 E. none of the aboveI need help figuring out how to draw this from this information (H NMR data) C8H16O2- 4.8(s,2H) 2.4(q,2H) 1.6 (s,9H) 1.4 (t, 3H) ---Can you explain what each thing means so I can draw the other ones myself Thank you ♡