Find the maximum value of f(x)=−5x2+5x+6 on the interval [−20,20]

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A: f(x)=(2x3+5)7  Then f'(x)=7(2x3+5)7-1×d dx(2x3+5)  f'(x)=7(2x3+5)6×6x2  f'(x)=42x2(2x3+5)6

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Q: In v3 2e" Ve2a + 1

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A: I have stated the used formula in the solution

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A: Please refer to the image below

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A: A detailed solution is given below

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A: Here we have to draw tangent lines at a given point on the graph. 

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