Find the NA here: Size 250*350 mm Ast = 1200 mm sq Fe 250 M25

Q: Ya = 1+e

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Q: PROBLEMS Exercise 1: (Upload in the Canvas) The figure below is a 3 blocks. The two MN kgs block was…

A: Equilibrium equations: Equilibrium equations are used to solve the unknown forces that are acting on…

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Q: (6 years), (K=T1%), 0%). Calculate the Design Hour Volume (DHV) :- * O DHV = 1344 %3D

A: It js proportion of AADT in the peak hour in the predominant direction of traffic flow. DDHV= AADT*…

Q: 1 = l2 The radius is (mm) 100mm

A: Given:- Ix1=Ix2 To find:- radius

Q: 2.5 ft, 2.5 ft, 5ft Rax 20 lb 40 lb Ray Rbx Rby Cx

A: Given -

Q: Given the figure below. Find the momemt of F about O. 4 ft F - (100- 120+75k) Ib 3 ft 5 t.

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Q: Ločate the centroids of the profilés as shown in Figure. The méasurements are given in + 15- 32

A: to find centroid

Q: (3x°y - x²) dx + ex dy 2 et3

A: Solutions using Exact Equation,

Q: Determine the moment of each force about the bolt located at A (Figure 1). Take Fa = 50 lb. Fc = 50…

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Q: d²u du What is the order of +t dt2 + 3u = 1? A. Order 1 B. Order 2 C. none Answer:

A: To find :- order of given differential equation

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Q: 1 for the System Shown below Calculate the Pressune Point A. Q/1 A O 15omm Datum

A: At point 1 Datum head Z1=3+2.1=5.1 mand pressure is atmospheric p1=0And velocity v1=0At point A…

Q: Civil Englne eing Verify whether the following are valid potential functions: (i) = 4x² – 5y² () ¢ =…

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Q: 400 lb/ft Pc = 400 lb 200 lb/ft A BY E |C D, + 2 ft → -2 ft→|1 1 – 4 ft-

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Q: Steel rod Steel rod A = 900 sq. mm A = 900 2 m sq. mm Copper A = 1200 2 m ww bs A B 1m 1 m

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Q: The centroid of the T-section shown is 2.8 inches above the base and x is 6. What should be the…

A: given- a  T section with C.G at 2.8'' above the base required- to find base 'b' to satisfy the given…

Q: Lim x25X+ 2 2X+ 2X-1 .3 メ→。

A: To evaluate: limx→∞x2-5x+22x3+2x-1

Q: 900 lb · ft 500 lb/ft 900 lb · ft A C B -3 ft 6 ft 6 ft -3 ft-

A: solution first find the reactions at the supports consider ∑Fy=0Ay+By=500x12=6000lbconsider…

Q: Take that a = 38 mm. (Figure 1) Part A Determine the moment of inertia of the beam's cross-sectional…

A: for flange section     b1=6a   and depth   d1=afor web section  width   b2=a  and  depth…

Q: Ci Engineering • Fluid Mechanics including Hya Verify whether the following are valid potential…

A: Given data: i) ϕ=2x+5yii) ϕ=4x2-5y2

Q: HI= BM+BS RL SNO BS IS FS HI RL 1.115 0:745 7245 1-065 O'785 1.315 2150 845 325-675 150 326-825…

A: student must write data as given below since the BS are the reading which are done from already…

Q: 400 lb /ft. - 1600 lb 12 R Fia. P-333.

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Q: Example: Copper Material Distance between anchor= 100 mm L = Im h = 6.5mm, b = 25.5 mm I…

A: Given data: Distance between the anchor = 0.1 m L= 1m h=6.5 mm b= 25.5 mm I=583.6 mm4. Y=3.25 mm

Q: D E F В H A R K M P 300 kN 8 panels @ 5 m 40 m- Dimensions in meters 6.25 6.0 5.5

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Q: 500 lb 400 lb B 4 ft - 3 ft-–3 ft: - 3 ft- -3 ft

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Q: Verify whether the following are valid potential functions: ) = 2r + 5y (i) = 4x²– 5y?

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Q: d B E C 654 P₁ 60 1.L F ( H P2 75 5 panels @ 4.50 m = 22.50 m 4.50 m 6.0 m

A: check the stress in member BD, DE, and EG using method of sections

Q: 3 3 (3x"y²- x²) dy + (4x°y- 2xy) dx = SOve t. %3D

A: To solve the given differential equation.   Given: 3x4y2-x2dy+4x3y3-2xydx=0   Our first step will be…

Q: 400 lb/ft A C B E-4 ft - 4 ft

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Q: 1.5m (20+CN) KN CN is the last digit of your cellphone Number 1.5m Doble shear bolt design support…

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Q: segment AB in ksi. final answer to whole number T2 L2

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Q: 80. R.C.C. was developed and first used by:

A: answer of this is option C

Q: 160 Ib/ft 400 Ib 400 lb 100 Ib/ft - on- 10 ft 5t 3 ft- 3 ft R: Ra R Re

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Q: Find the Resultant mom ent about point A. Soo mm 300 m SON 15N 5ON 30 30 -oSE m

A: The distance of force 15N from point A in vertical direction = 350Sin30°= 175mmThe distance of force…

Q: Evaluate the following: a. L{5} b. L{t³}

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Q: Q/3 For the assembly shown in Figure the temperature raised from 20° C to 30° C, what is the new Gap…

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Q: Find the NA here: Size 250*350 mm

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Q: Assuming the plates are 15 feet tall and 6 feet long, and are arranged with three mechanical…

A: Given Data The plates are 15 ft tall and 6 ft long H = 15 ft L = 6 ft Number of mechanical fields…

Q: 24 KIv. Specific weight,

A: Given:- Volume=4300L Weight=24kN To find:- a) Specific Weight b)Mass Density c)Specific Gravity

Q: 150 lb/ft 300 lb-ft 12 ft

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Q: DE F G H R K LM N O P 300 kN - 8 panels @ 5 m= 40 m - Dimensions in meters 6.25 0'9 5.5 4.5

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Q: 1) Brass weight is to be attached to the bottom of a cylinder which is made froi uniform material…

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Q: ALL PROBLEMS, DETERMINE To FOR THE AFD, SFD, AND BMD MAKING SURE SHOW ALL WORK REQUIRED To OBTAIN…

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Q: dy 2- Find for the following function: dx A- y = 3cosx B- y = x6. cscx

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Q: M/L M,/L

A: Given: A simple supported beam with a concentrated moment Mo acting at the right support.  To…

Q: 5 5a 5b 5c Alaterally supported beam was designed for flexure. The beam is safe for shear &…

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Q: 1000 lb 400 lb/ft A B 5 ft 5 ft: FIXED CONNECTION 500 lb

A: Point c is fixed support At fixed support has 3 reactions 1. Horizontal reaction Rcx 2. Vertical…

Q: AN cm bkN dm D e m e m em

A: