Find the points on the graph of y = (2x²+1)(x-5) 4 where the tangent line Slope is 1. 0=y= (2x²+1) (x-1) (product Find the points=2001 = (n on the graph where thereS tangent Slope is 0.00014002010 +00. = (25) ab sal= (all +30 dy dx = 4x(x-1) + (2x²+1) Cx 0= 4x² - 4x + 2x² + 1 0 = 6x² - 4x + 1 X = -(-4) ± √(-4) ²-4 (6)(1)_ _4±-√16-24 216) 12 X=4± √√-8 12 * Ans X= NO Point on graph
Find the points on the graph of y = (2x²+1)(x-5) 4 where the tangent line Slope is 1. 0=y= (2x²+1) (x-1) (product Find the points=2001 = (n on the graph where thereS tangent Slope is 0.00014002010 +00. = (25) ab sal= (all +30 dy dx = 4x(x-1) + (2x²+1) Cx 0= 4x² - 4x + 2x² + 1 0 = 6x² - 4x + 1 X = -(-4) ± √(-4) ²-4 (6)(1)_ _4±-√16-24 216) 12 X=4± √√-8 12 * Ans X= NO Point on graph
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section: Chapter Questions
Problem 89RE
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