Find the points on the graph of y = (2x²+1)(x-5) 4 where the tangent line Slope is 1. 0=y= (2x²+1) (x-1) (product Find the points=2001 = (n on the graph where thereS tangent Slope is 0.00014002010 +00. = (25) ab sal= (all +30 dy dx = 4x(x-1) + (2x²+1) Cx 0= 4x² - 4x + 2x² + 1 0 = 6x² - 4x + 1 X = -(-4) ± √(-4) ²-4 (6)(1)_ _4±-√16-24 216) 12 X=4± √√-8 12 * Ans X= NO Point on graph

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section: Chapter Questions
Problem 89RE
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Question
PLEASE REVIEW THE EXAMPLE PROBLEM AND DO THE QUES 1 ACCORDINGLY!
2:25 7
Expert Q&A
Applied Calculus Class: Please see the completed
review example for reference.
and solve the given question. ( show all work).
Thanks! solve ques. 1
Find the points on
the graph of
y = (2x²+1)(x - 5)
where the tangent line
Slope is 1.
CHJAY
0₁y = (2x² + 1) (x-1) (+)
.5G
* Find the points 2001 = (nu
on the graph where the DaS
tangent slope is 0.00014002 She
120. = (25) a
+ão.
dy
x = 4x(x²-1) + 12x²+1)
dx
0= 4x² - 4x + 2x ²³² + 1
0 = 6x² - 4x +)
X=-(-4) ± √√(-4) ²- 4 (6) (1)
216)
X=4± √√-8
12
*
ماع) - ام
Ans
produck
Arule
39
=
Done
4± √₁
√16-24
12
X= NO Point on
graph
1000k
Transcribed Image Text:2:25 7 Expert Q&A Applied Calculus Class: Please see the completed review example for reference. and solve the given question. ( show all work). Thanks! solve ques. 1 Find the points on the graph of y = (2x²+1)(x - 5) where the tangent line Slope is 1. CHJAY 0₁y = (2x² + 1) (x-1) (+) .5G * Find the points 2001 = (nu on the graph where the DaS tangent slope is 0.00014002 She 120. = (25) a +ão. dy x = 4x(x²-1) + 12x²+1) dx 0= 4x² - 4x + 2x ²³² + 1 0 = 6x² - 4x +) X=-(-4) ± √√(-4) ²- 4 (6) (1) 216) X=4± √√-8 12 * ماع) - ام Ans produck Arule 39 = Done 4± √₁ √16-24 12 X= NO Point on graph 1000k
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