Find the potential difference across each resistor in the figure below. (R₁ = 5.25 №, R₂ = 3.900, R3 = 2.700, R4 = 1.700) 12.0 V 3.00 V I I I 18.0 V R3 i
Find the potential difference across each resistor in the figure below. (R₁ = 5.25 №, R₂ = 3.900, R3 = 2.700, R4 = 1.700) 12.0 V 3.00 V I I I 18.0 V R3 i
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter28: Direct-current Circuits
Section: Chapter Questions
Problem 28.21P: Consider the circuit shown in Figure P28.21 on page 860. (a) Find the voltage across the 3.00-0...
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and finding the potential difference across each resistor
Transcribed Image Text:Find the potential difference across each resistor in the figure below. (R₁
R₁ = 1.700)
12.0 V
R₁
R₂-
3.00 V 18.0 V
RA
R3
=
5.250, R₂
=
3.900, R3 = 2.700,
![Assume that the currents I₁, I2, and I3 are in the directions indicated by the arrows in the figure redrawn below.
(Enter your answers to at least four significant figures.)
a 1₂2
12.0 V
R₁
or
Solving for I₁ gives
1
R₂.
3.00 V
0
Im
R3
Applying Kirchhoff's junction rule at a gives
13 = 1₁ + 1₂.
[1]
Using Kirchhoff's loop rule starting at point a and going clockwise around the leftmost loop yields
RA
18.0 V
I
-3.00 V - R₂13 - R₁₁ + 12.0 V = 0.
X
0
I₁
= The correct answer is not zero. V
R₁
- (R₁)131
1₁
= The correct answer is not zero. A
A) - (0
The correct answer is not zero.
.)13. [2]
3'
X](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F21e8a523-579f-40b9-8f0a-805524283a8d%2F20effa46-841d-4b30-922a-34de1079cd73%2F754xxnq_processed.png&w=3840&q=75)
Transcribed Image Text:Assume that the currents I₁, I2, and I3 are in the directions indicated by the arrows in the figure redrawn below.
(Enter your answers to at least four significant figures.)
a 1₂2
12.0 V
R₁
or
Solving for I₁ gives
1
R₂.
3.00 V
0
Im
R3
Applying Kirchhoff's junction rule at a gives
13 = 1₁ + 1₂.
[1]
Using Kirchhoff's loop rule starting at point a and going clockwise around the leftmost loop yields
RA
18.0 V
I
-3.00 V - R₂13 - R₁₁ + 12.0 V = 0.
X
0
I₁
= The correct answer is not zero. V
R₁
- (R₁)131
1₁
= The correct answer is not zero. A
A) - (0
The correct answer is not zero.
.)13. [2]
3'
X
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