Find the power absorbed by each of the elements in Fig. 1.26. I = 10 A 10 V 8 V 4 A P2 |14 A P4 P5 30 V Pi 20 V P3 12 V 0.41 Rgure 1.26
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![Find the power absorbed by each of the elements in
Fig. 1.26.
I= 10 A
10 V
8 V
4 A
P2
14 A
P4
P5
30 V
Pi
20 V
P3
12 V
0.41
Fgure 1.26](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd5888a67-b575-4bff-a474-156b825e6e58%2Fd24a88c0-95c1-4ce6-9077-29fbba4613e0%2F8ubvgk_processed.png&w=3840&q=75)
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- ll SuperNe 4G 3:00 PM C @ 6% Question 9 1 points Save A Power supply circuit is delivering0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to I2-Dc 205A 220V omsh 5OHZ O 001 F O 0 02 F O 00167 F O None of the aboveb) Use the ALU 74181 in the figure below and the tables (one is enough; second maybe, need to check the new kit) to implement : A + B, A – B, A. B. (MSB) (LSB) 10 (MSB) F3 F2 F1 FO S3 Cn+4 16 s2 20 U14 15 S1 14 so A3 A2 A1 AO B3 B2 B1 B0 M Cn 24 23 22 21 28 27 T26 25 (LSB) (MSB) (LSB)(MSB) (LSB) And given that under M = 1 the circuit performs the following arithmetic and logic functions according to Table 11.1. Input selection S3 Output M-H S2 SI Cn=L. F3 F2 F1 FO A 1 -A В -B A&B AxB 1 A'B 1 Ax(-B) (-A)xB (-A)x(-B) 1 1 ACTIVE HIGH DATA M-L: ARITHMETIC OPERATIONS SELECTION M-H LOGIC s3 s2 s1 so Ino carry) (with carry) F-A PLUS 1 F- LA + B) PLUS 1 F- (A + BI PLUS 1 FUNCTIONS L L F-A F-A+B F-AB F-A H FA+B F-A+T F- MINUS 1 12s COMPL) F-A PLUS AB F- IA + BI PLUS AB L L L L F-0 F-ZERO F- AB F-A PLUS AB PLUS 1 F- (A + BI PLUS AB PLUS 1 L L L H L F-AOB F- AB L L F-A MINUS B MINUS 1 F-A MINUS B F- AB MINUS 1 F- A F-A PLUS AB PLUS1 F-A PLUS B PLUS 1 F- IA + B PLUS AB PLUS 1 L H L F-A PLUS AB…PUT THE Fouawwb OPENAIONS IN THE CocRECT OnDER N ORDER TO FABRICATE A SCHOTTKY DeoDE ON n t SUBSTRATE. PROPER OCDER A EXPOSE SCHOTTKY METAL LIFT OFF SHOTTEY METAL CLEAU SAMPLE D MEASURE DEUICE E CLEAN SAMPLE ANNEAL OHMIC METAL G DEPOSIT BACKSIDE OHMIC METAL DEPOSIT SCHOTTLY METAL CLEAN SAMPLE 3 DEVELOP SatoTTy METAL SPIN COAT NEG. RESIST
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- Consider the circuit shown in the figure below with R1=16 ko and R=8 klQ. The Zener diode voltage is Vz = 3.5 V, then the currents Iz and lu respectively, are equal to: Ri of ww RL 20 V O a. 0.594 mA, 0.438 mA Ob. 0.394 mA 0.237 mA Oc 0.794 mA, 0.637 mA O d. 0.994 mA, 0.838 mADetermine the potential Uab and the current IE1 in the figure1) The term Bi is defined as Select one: O a. Negative change in reference bus power to the power change DPi on bus i O b. All of these 1/Pfi Clear my choice
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