Problem My question is why we did not take them as parallel to find the inductance in coil 1

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Problem My question is why we did not take them as parallel to find the inductance in coil 1
ons manual o...
E CircuitLab | Editing..
. Printable Calendar...
Quick Linear Regres...
S Solving of differenti..
A coin is biased wit...
O At a certain un
2 / 2
146%
Problem 4
The magnetic circuit shown in
the figure has two windings and
two air gaps. The core can be
assumed to
| 82 |-
Core, u
Area A2
be of infinite
permeability.
dimensions are indicated in the
The
core
Arca A
N, turns
figure.
inductances of windings 1 and 2
and the mutual inductance
between the windings.
Find
the
self-
Na turns
Problem 5
A system of three coils on an ideal core
is
shown
in
the
fig,
where
N1=N3=2N2=500
turns,
gl=2g2=2g3=4mm, and A=1000mm2.
81
83
A
N3
Calculate:
Transcribed Image Text:ons manual o... E CircuitLab | Editing.. . Printable Calendar... Quick Linear Regres... S Solving of differenti.. A coin is biased wit... O At a certain un 2 / 2 146% Problem 4 The magnetic circuit shown in the figure has two windings and two air gaps. The core can be assumed to | 82 |- Core, u Area A2 be of infinite permeability. dimensions are indicated in the The core Arca A N, turns figure. inductances of windings 1 and 2 and the mutual inductance between the windings. Find the self- Na turns Problem 5 A system of three coils on an ideal core is shown in the fig, where N1=N3=2N2=500 turns, gl=2g2=2g3=4mm, and A=1000mm2. 81 83 A N3 Calculate:
3:40 1
a)
The magnetic circuit is shown below:
Core
Arca A
Area A
N, tums
N turas
81
Coil 1
The total flux linkage due to coil 1 is the flux
linkage due to both the area, the magnetic
field in each area due to the coil is given as:
B1
91
B2
92
The self-inductance of coil 1 is calculated as:
1 = N;(A, B1)+N1(A2B2)
1 = N; (A, x ) +N; (A2 × )
4)+N: (A2 ×
9i
1 = N;²I;( + )
92
L11 = HoN12 + HoN¡² A2
g1
Transcribed Image Text:3:40 1 a) The magnetic circuit is shown below: Core Arca A Area A N, tums N turas 81 Coil 1 The total flux linkage due to coil 1 is the flux linkage due to both the area, the magnetic field in each area due to the coil is given as: B1 91 B2 92 The self-inductance of coil 1 is calculated as: 1 = N;(A, B1)+N1(A2B2) 1 = N; (A, x ) +N; (A2 × ) 4)+N: (A2 × 9i 1 = N;²I;( + ) 92 L11 = HoN12 + HoN¡² A2 g1
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