Find the probability that if Air-USA books 23 persons, not enough seats will be available. prob = Is this probability low enough so that overbooking is not a real concern for passengers if you define unusual as 5% or less? O yes, it is low enough not to be a concern O no, it is not low enough to not be a concern What about defining unusual as 10% or less? O yes, it is low enough not to be a concern O no, it is not low enough to not be a concern

College Algebra
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Author:Ron Larson
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Chapter8: Sequences, Series,and Probability
Section8.7: Probability
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Air-USA has a policy of booking as many as 23 persons on an airplane that can seat only 21. (Past
studies have revealed that only 83% of the booked passengers actually arrive for the flight.)
Find the probability that if Air-USA books 23 persons, not enough seats will be available.
prob =|
Is this probability low enough so that overbooking is not a real concern for passengers if you define
unusual as 5% or less?
O yes, it is low enough not to be a concern
O no, it is not low enough to not be a concern
What about defining unusual as 10% or less?
O yes, it is low enough not to be a concern
O no, it is not low enough to not be a concern
Transcribed Image Text:Air-USA has a policy of booking as many as 23 persons on an airplane that can seat only 21. (Past studies have revealed that only 83% of the booked passengers actually arrive for the flight.) Find the probability that if Air-USA books 23 persons, not enough seats will be available. prob =| Is this probability low enough so that overbooking is not a real concern for passengers if you define unusual as 5% or less? O yes, it is low enough not to be a concern O no, it is not low enough to not be a concern What about defining unusual as 10% or less? O yes, it is low enough not to be a concern O no, it is not low enough to not be a concern
Expert Solution
Step 1

Given :

Air-USA has a policy of booking as many as 23 persons on an airplane that can seat only 21.

Studies have revealed that only 83% of the booked passengers actually arrive for the flight.

Therefore, the probability of a person arrive is 0.83

Let X denotes number of passengers arriving 

It will follow a Binomial distribution

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