Find the probability that none of the households are tuned to Found?

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Counting And Probability
Section9.3: Binomial Probability
Problem 2E: If a binomial experiment has probability p success, then the probability of failure is...
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Find the probability that none of the households are tuned to Found?

The television show Found has been successful for many years. That show recently had a share of
20, meaning that among the TV sets in use, 20% were tuned to Found. Assume that an advertiser
wants to verify that 20% share value by conducting its own survey, and a pilot survey begins with 14
households have TV sets in use at the time of a Found broadcast.
(Round answers to four decimal places)
Find the probability that none of the households are tuned to Found.
P(none) =
Find the probability that at least one household is tuned to Found.
P(at least one) =
Find the probability that at most one household is tuned to Found.
P(at most one) =
If at most one household is tuned to Found, does it appear that the 20% share value is wrong? (Hint:
Is the occurrence of at most one household tuned to Found unusual?)
O yes, it is wrong
O no, it is not wrong
Transcribed Image Text:The television show Found has been successful for many years. That show recently had a share of 20, meaning that among the TV sets in use, 20% were tuned to Found. Assume that an advertiser wants to verify that 20% share value by conducting its own survey, and a pilot survey begins with 14 households have TV sets in use at the time of a Found broadcast. (Round answers to four decimal places) Find the probability that none of the households are tuned to Found. P(none) = Find the probability that at least one household is tuned to Found. P(at least one) = Find the probability that at most one household is tuned to Found. P(at most one) = If at most one household is tuned to Found, does it appear that the 20% share value is wrong? (Hint: Is the occurrence of at most one household tuned to Found unusual?) O yes, it is wrong O no, it is not wrong
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