Find the probabillty using the normal distribution: P(-2.69

Q: For a standard normal distribution, find: P(z > -1.12) (round to 3 decimal places)

A: We have to find the probability for a standard normal distribution. P (Z > -1.12).

Q: Use the standard normal distribution to find P(-2.25 < z < 0).

A: we have to find probability from z table.

Q: For a standard normal distribution, find: P(z > -2.64) Express the probability as a decimal rounded…

A: Solution-: We find,

Q: For the standard normal distribution, compute Z0.69. Use Excel and round the answer to two decimal…

A: Given: Excel function =NORM.S.INV(PROBABILITY)

Q: For a standard normal distribution, find: P(z > -0.59) Express the probability as a decimal rounded…

A: Given data  Standard normal distribution P(z&gt;-0.59)=?

Q: For a standard normal distribution, find: P(-0.93 < z < 1.67)

A: From the provided information, P (-0.93 &lt; z &lt; 1.67)

Q: For a standard normal distribution, find: P(z > c) = 0.5296 Find c. (round to 2 decimal places)

A: We have given a standard normal distribution. P (Z &gt; c) = 0.5296 We have to find the value of c.

Q: for a standard normal distribution,find: p(z>1.62)

A: Given that z is standard normal random variable:

Q: Find the indicated probability using the standard normal distribution. P(z< -1.42)

A: We will use Standard Normal table to find the required probability.

Q: In the standard normal distribution, find the z value that corresponds to the 78" percentile. Use a…

A: To find z at 78th percentile.

Q: Use the Central Limit Theorem to find the probability of the indicated event, assuming that the…

A:

Q: For a standard normal distribution, find: P(z > -1.93) Express the probability as a decimal…

A: From the provided information, P (z &gt; -1.93)

Q: Find the indicated probability using the standard normal distribution. P(0 <z<0.655)

A: The required probability is calculated as follows: P0&lt;z&gt;0.655=PZ≤0.655-PZ≤0…

Q: For a standard normal distribution, find: P(-2.76 <z<2.32)

A: The z values are -2.76 and 2.32.

Q: For a normal distribution, find the z-score that cuts off the top 70.71% of area. Round to 2 decimal…

A:

Q: For a standard normal distribution, find: P(1.75 <z< 2.03)

A:

Q: For a standard normal distribution, find: P(z < -1.74)

A: Let Z ~N(0,1). P[Z&lt;-1.74]=Φ(-1.74)

Q: For a standard normal distribution (μ=0μ=0 and σ=1σ=1), find the following probability, and please…

A: Given information Mean µ = 0 Standard deviation σ = 1

Q: For a standard normal distribution, use the Empirical Rule: P(z > 2) = _____ % answer as a decimal…

A: We know that empirical rule is also called as 68-95-99.7 percent rule. Empirical rule-

Q: For a standard normal distribution, find: P(z > -2.84) Express the probability as a decimal rounded…

A: Obtain the probability of z greater than –2.84.   The probability of z less than –2.84 is obtained…

Q: For a standard normal distribution, find: P(z> c) = 0.9402 Find c. Round to 2 decimal places

A: GivenP(z&gt;c)=0.9402

Q: For a standard normal distribution, find: P(-2.84 < z < 1.53)

A:

Q: In the standard normal distribution, find the z value that corresponds to the 78" percentile. Use a…

A: Given : We need to calculate the z-value corresponding to 78th percentile   We know, a 90th…

Q: Find the probability using the normal distribution. Use a graphing calculator and round the answer…

A: The z-scores are 0 and 1.66.

Q: For a standard normal distribution, find: P(-1.12 < z < -0.92) (round to 3 decimal places)

A: The z-score follows standard normal distribution.

Q: For a standard normal distribution, find: P(z < -0.77) Express the probability as a decimal rounded…

A: Given that z is a standard normal distribution.  So, z follows a normal distribution with mean=0 and…

Q: - th In the standard normal distribution, find the z value that corresponds to the 76 percentile.…

A: Answer: Z=0.7600

Q: find the proportions of a values in the standard normal distribution that are greater than -0 47

A:

Q: Find the indicated probability using the standard normal distribution. P(z< - 1.59)

A: Given, z=-1.59

Q: For a standard normal distribution, find: P(z > 1.72) Express the probability as a decimal rounded…

A: P(Z&gt;1.72) is given.It is right tailed.

Q: For a standard normal distribution, find: P(-0.68 < z < 1.52)

A:

Q: For a standard normal distribution, find: P(z > 0.97) Express the probability as a decimal rounded…

A:

Q: Find the probability using the normal distribution. Use a graphing calculator and round the answer…

A: Given that  The distribution is normal. P(0&lt;z&lt;0.96) The graph represents as follows Shaded…

Q: For a standard normal distribution, find: P(z > 1.76) Express the probability as a decimal rounded…

A: Given Information:To find out Pz&gt;1.76

Q: In the standard normal distribution, find the z value that corresponds to the 83 percentile. Use a…

A: To find value z at 83th percentile using TI-84

Q: Find the probability associated with the standard normal distribution. P(Z greater than or equal to…

A: Required shaded area under the normal curve.

Q: For a standard normal distribution, find: P(z < -0.22) Express the probability as a decimal rounded…

A: We have to find P(z&lt;-0.22)  Graphically,  We have to find shaded area.

Q: For a standard normal distribution, find: P(-2.79 < z < 0.77)

A: From the provided information, P (-2.79 &lt; z &lt; 0.77)

Q: For a standard normal distribution, find: P(z < -0.73) Express the probability as a decimal rounded…

A: Solution :  For standard normal distribution, z = x-μσ P(z &lt; -0.73) : To find this probability ,…

Q: For a standard normal distribution, find: P(z > 2.54) Express the probability as a decimal rounded…

A: standard normal distribution   p(z&gt;2.54) = ?

Q: For a standard normal distribution, find: P(z > c) = 0.0808 Find c.  (round to 2 decimal places)

A: Draw the normal curve and shade the area of 0.0808 to the right of c.

Q: For a standard normal distribution, find: P(-1.39 < z < -0.35)

A: P(-1.39 &lt; z &lt; -0.35)

Q: Find the indicated probability using the standard normal distribution  P (0&lt;z&lt;0.575)

A: The probability between z= 0 and Z= 0.575 is calculated as shown below:

Q: For a standard normal distribution, find: P(z < -1.71) Express the probability as a decimal rounded…

A: We have to find out given probability...

Q: For a standard normal distribution, find: P(z > -1) Express the probability as a decimal rounded to…

A:

Q: For a standard normal distribution, find: P(z > c) = 0.9402 Find c. Round to 2 decimal places

A: Z follows standard normal distribution with mean 0 and standard deviation 1 P( Z &gt; c ) = 0.9402

Q: Find the indicated probability using the standard normal distribution.   ​P(- 0.25&lt;z&lt;0​)

A: z-score:Consider the random variable X that follows a distribution with mean µ and the standard…

Q: For a standard normal distribution, find: P(-2.83 < z < 1.43) [Round your answer to two decimal…

A: From the given information we have to find P( -2.83 &lt; Z &lt; 1.43)

Q: For a standard normal distribution, find: P(z < 1.64) Express the probability as a decimal rounded…

A:

Q: For a standard normal distribution, find: P(z < c) = 0.6292 Find c rounded to two decimal places

A: Given that  P( Z &lt; c ) = 0.6292 By standard normal table of z

Inverse Normal Distribution

The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.

Mean, Median, Mode

It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.

Z-Scores

A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.