Question
Asked Oct 1, 2019

Find the real zeros of f. Use the real zeros to factor of f.

(f)=x3-10x2+28x-16

 

check_circleExpert Solution
Step 1

The given expression is,

x-10x228x -16
help_outline

Image Transcriptionclose

x-10x228x -16

fullscreen
Step 2

Substitute x=4 in above equation.

(4)-10(4) 28(4)-16=64-160+112-16
= 0
help_outline

Image Transcriptionclose

(4)-10(4) 28(4)-16=64-160+112-16 = 0

fullscreen
Step 3

This imply x-4 is a factor of given expression....

- 6x+ 4
x- 4x10x228x-16
x34x2
- 6x2 +28.x
-6x2 24x
+
4х -16
4х —16
- +
+
help_outline

Image Transcriptionclose

- 6x+ 4 x- 4x10x228x-16 x34x2 - 6x2 +28.x -6x2 24x + 4х -16 4х —16 - + +

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour*

See Solution
*Response times may vary by subject and question
Tagged in

Math

Calculus

Functions

Related Calculus Q&A

Find answers to questions asked by student like you

Show more Q&A add