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Find the round-off error of the following using 5 significant digits: 1. 1 3 2. tan 150 3. 1 — п 4. V115 5. In 12

Find the round-off error of the following using 5 significant digits: 1. 1 3 2. tan 150 3. 1 — п 4. V115 5. In 12

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter1: Expressions And Functions
Section1.5: Descriptive Modeling And Accuracy
Problem 3CYU
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Find the round-off error of the following using 5 significant digits: 1. 1 3 2. tan 150 3. 1 — п 4. V115 5. In 12
Transcribed Image Text:Find the round-off error of the following using 5 significant digits: 1. 1 3 2. tan 150 3. 1 — п 4. V115 5. In 12
Round-Off Error 1. Given: 2. Given: 3. Given: Note that the e constant or Actual Value = Actual Value = : 0.666666666666 ... Rounded – Euler's number is a 2.003458764 mathematical constant. Rounded – The e constant is real and off Numerical Value = off Numerical Value = irrational number that is 2.0035 0.66667 equal to: e = 2.718281828459...= Solution: Solution: Round – off Error = Actual Value – Actual Value *Property of STI Page 2 of 4 03 Handout 2 STI IT1903 Since the problem states Rounded – Round – off Error = Actual Value – off Numerical Value Round – off Error = 2.003458764 – 2.0035 Round – off Error = -0.000041236 that each number is Rounded – represented by using 5 significant digits, thus the Rounded off Numerical Value Round – off Error = 0.666666666666 – - off numerical value = e = 2.7183 0.66667 Round – off Error = -0.000003333334 Solution: Round – off Error = Actual Value – Rounded – off Numerical Value Round – off Error = 2.718281828459 – 2.7183 Round – off Error = -0.000018171541
Transcribed Image Text:Round-Off Error 1. Given: 2. Given: 3. Given: Note that the e constant or Actual Value = Actual Value = : 0.666666666666 ... Rounded – Euler's number is a 2.003458764 mathematical constant. Rounded – The e constant is real and off Numerical Value = off Numerical Value = irrational number that is 2.0035 0.66667 equal to: e = 2.718281828459...= Solution: Solution: Round – off Error = Actual Value – Actual Value *Property of STI Page 2 of 4 03 Handout 2 STI IT1903 Since the problem states Rounded – Round – off Error = Actual Value – off Numerical Value Round – off Error = 2.003458764 – 2.0035 Round – off Error = -0.000041236 that each number is Rounded – represented by using 5 significant digits, thus the Rounded off Numerical Value Round – off Error = 0.666666666666 – - off numerical value = e = 2.7183 0.66667 Round – off Error = -0.000003333334 Solution: Round – off Error = Actual Value – Rounded – off Numerical Value Round – off Error = 2.718281828459 – 2.7183 Round – off Error = -0.000018171541
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