Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a margin of error of 1 percentage point and use a confidence level o 90%. Complete parts (a) and (b) below. ... a. Assume that p and q are unknown. n3= (Round up to the nearest integer.)

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A: From the provided information, Margin of error (E) = 0.04 Confidence level = 98% The z value at 98%…

Q: In a study of government financial aid for college students, it becomes necessary to estimate the…

A: Solution: a. From the given information, confidence level is 0.99 and E=0.02.

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Q: Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

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A: Given ,sample size (n)=43degrees of freedom(d.f)=n-1=43-1=42α=1-0.90=0.1α2 =0.05

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A: Dear student, If you find this solution helpful please upvote ? it. The solution is given below:

Q: Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E.…

A: Given that  Assumed that the sample is used to estimate a population proportion p. Sample size (n) =…

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Q: Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E.…

A: Solution: Given information: n= 220 Sample size  x= 110 successes  p^=xn=110220= 0.5 Sample…

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A: given that, n = 570 p^=0.8 confidence level = 95%

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Q: If n=340 and p (p-hat) =0.23, find the margin of error at a 95% confidence level Give your answer to…

A: Given,n=340p^=0.23α=1-0.95=0.05α2=0.025Z0.025=1.96

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A: Solution: a. From the given information, confidence level is 0.95 and E=0.03.

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Q: Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E.…

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Q: If n=350 and ˆpp^ (p-hat) =0.64, find the margin of error at a 90% confidence level Give your…

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A: Given that Sample size n = 342 Sample proportion = 37.1% = 0.371 Confidence level = 99.5%

Q: find the margin of error at a 90% confidence level

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Q: Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E.…

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Q: Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E.…

A: Given data,n=323p=50.2%=0.502z value at 95 % confidence is Zc=1.96Margin of error(ME)=?

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